Q: What is the median of 75 75 75 85 80 90 and 90?

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75, 80, 85, 90, 95, 100, 105 and just keep adding 5 until you get to infinity.75, 80, 85, 90, 95, 100 and just keep adding five until you get to infinity.

65, 70, 75, 80, 85, 90 and 95.

Simply keep adding a 5: 75 80 85 90 95 100 and so on as far as you wish.

81, 82, 84, 85, 86, 87, 88. 80 and 90 are composite too

The composite numbers are: 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86 ,87, 88

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It is 85, the middle value, between 80 and 90.

Median of the set = arithmetic mean of 75 and 85 = 80

80

The mean is 85.5 The median is 88.5 The mode is 90

90

90

85

80 75 + 70 + 80 = 225 80 + 85 + 90 = 255 225 + 255 = 480 six numbers so 480 / 6 = 80

83

Write the data in an increasing order:40 60 79 80 90 90 98 99Since the number of data is even, the median will be the average of the two data that are in the middle (80 and 90).So the median of the data is 85, (80 + 90)/2.

the median is 86. What you do is put the numbers in order from least to greatest and cross one off from each side till you get to the middle number. 80 85 86 90 94

100,90,85, 90,80,75,80.90. Rearrange the terms in rank order. 75,80,80,85,90,90,90,100. MEAN : Add all the terms together and divide by the number of terms. Hence:- (75+80+80+85+90+90+90,+100)/8 => 690/8 = 86.25 MEDIAN : Is the Absolute middle term. Since there are an even number of terms, we take the two middle terms, which are 85 & 90. (NB This leaves three terms to the left of '85' and three terms to the right of '90'. ). Add these two terms and divide by '2'. Hence (85+90) / 2 = 87.5 MODE : Is the most frequent term. The one term that appears most often. In this case it is '90', as there are three lots of '90', but only two lots of 80, and only one each of the remaining terms. = 90. .