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Q: What is the median of 90 85 80 90 95 90 and 100?

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80

It is 89

80, 81, 82, 84, 85, 86, 87, 88, 90

85

You cannot find the original set, but you can create one set that matches the criteria.With nine numbers and a median of 80, the 5th number is 80: {x, x, x, x, 80, x, x, x, x}With a mode of 75, there must be more 75s that any other number. The easiest way to do this is to have two 75s and one of each other number, so the set is now: {x, x, 75, 75, 80, x, x, x, x}.Finally, with a mean of 85, the easiest way to create nine numbers with such a mean is to split the nine numbers into pairs, one greater than 85 and one less than 85, which together sum to 85 x 2 = 170, and a single number of 85. One such set of nine numbers is {50, 60, 70, 80, 85, 90, 100, 110, 120}. However, there are some previously decided numbers (above), so this set can now be adjusted to accommodate those numbers:First, there needs to be two 75s, so increase the first number before 75: it is 70 so increase it to 75 by adding 5, which means that 5 in all must be added to some/all of the numbers after the 85.Second, decrease the first number after the 75: it is 80, so decrease it to 75 by subtracting 5, which means that 5 - 5 = 0 must now be added to the numbers after the 85 (ie they can be left alone).Third, the median must be 80, but it is currently 85 so reduce it to 80 be subtracting 5, which must be added to the numbers after it.Now add the 5 required ensuring that there is no more than one of each number created.Some sets created:{50, 60, 75, 75, 80, 90, 100, 110, 125}{50, 60, 75, 75, 80, 93, 101, 111, 120}{50, 60, 75, 75, 80, 95, 100, 110, 120}Staring with another set {70, 75, 80, 82, 85, 88, 90, 95, 100}, the adjustments are: 80 -> 75, 82 -> 78 (less than 80, greater than 75), 85 -> 80 which means there is 5 + 4 + 5 = 14 needed to be added to the right 4 numbers which can lead to the sets:{70, 75, 75, 78, 80, 88, 90, 95, 119}{70, 75, 75, 78, 80, 91, 94, 97, 105}etc

Related questions

90

85

It is 85, the middle value, between 80 and 90.

Median of the set = arithmetic mean of 75 and 85 = 80

80

The mean is 85.5 The median is 88.5 The mode is 90

The median of those numbers is 90.

Write the data in an increasing order:40 60 79 80 90 90 98 99Since the number of data is even, the median will be the average of the two data that are in the middle (80 and 90).So the median of the data is 85, (80 + 90)/2.

80

the median is 86. What you do is put the numbers in order from least to greatest and cross one off from each side till you get to the middle number. 80 85 86 90 94

100,90,85, 90,80,75,80.90. Rearrange the terms in rank order. 75,80,80,85,90,90,90,100. MEAN : Add all the terms together and divide by the number of terms. Hence:- (75+80+80+85+90+90+90,+100)/8 => 690/8 = 86.25 MEDIAN : Is the Absolute middle term. Since there are an even number of terms, we take the two middle terms, which are 85 & 90. (NB This leaves three terms to the left of '85' and three terms to the right of '90'. ). Add these two terms and divide by '2'. Hence (85+90) / 2 = 87.5 MODE : Is the most frequent term. The one term that appears most often. In this case it is '90', as there are three lots of '90', but only two lots of 80, and only one each of the remaining terms. = 90. .

The MEDIAN is the number in the middle. In order to find the median, you have to put the values in order from lowest to highest, then find the number that is exactly in the middle. For example : 80 85 90 90 90 100 ^ since there is an even number of values, the MEDIAN is between these two, or it is 90. Notice that there is exactly the same number of values above the median as below it! Its that simple.

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