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There are 1.0001 moles.
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∙ 8y ago
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What is the mole fraction of O2 in the mixture 02?
It is 100%.
What is the composite of air?
Composition of air (% by volume):Nitrogen (N2): 78.09%Oxygen (O2): 20.95%Argon (Ar): 0.93%Carbon dioxide (CO2): 0.038%Others (less than 0.002% each): Neon (Ne), Helium (He), Krypton (Kr), Hydrogen (H2), Xenon (Xe).See the Related Links for "MIStupid.com: Composition of air" to the bottom for the answer.Our atmosphere also contains water vapor. In addition, Earth's atmosphere contains traces of dust particles, pollen, plant grains and other solid particles.
How many grams of O2 are in 15 moles of O2. with work shown?
15 moles O2 (32 grams/1 mole O2) = 480 grams
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
Which best represents the number of moles in exactly 64 grams of oxygen (O2)?
The number of moles in exactly 64 grams of oxygen (O2) is two.
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
4.50 moles NO2 X (46 grams NO2) / (1 mole NO2) x (4 moles NO2) / (7 moles O2) x (1 mole O2) / (32 gm O2) = 3.70 grams O2
How many grams are there in 2.047 moles of O2?
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
How do you figure out 3.2 moles of o2?
The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------
What is the mass of water when 4gm hydrogen and 64gm oxygen combined together nd how?
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
How many grams of oxygen gas will react with 77.28 grams of ethane in 2 C2H6 plus 7 O2 equals 4 CO2 plus 6H2O?
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
How many moles of H2O are product from reaction of 355 g of O2?
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
How many moles of oxygen gas O2 are in 64 grams of O2?
The answer is 2 moles.
How do you convert an element to moles?
to convert an element to moles you need to setup and equation, for our example we will be using 5g of O2 or oxygen. You need to know what O2's molar mass is as well, it is 32g. So the equation would be 5g of O2 / 32 = .16 moles of O2. So to convert moles to grams all you do is multiply the moles given by the molar mass of the element/compound and you have your grams Hoped this helped : )
What is the mass of 2.50 moles of oxygen gas?
The relationship between number of moles and mass is: n = m/MW Where n is the number of moles, m is the mass in grams and MW is the molecular weight (or molecular mass). Subsituting the numbers into the equation: 2.5 mol = m/32 (from O2(g), 16 from each oxygen) m = 2.5 * 32 = 80 grams This also means that there is approximately 1.5 x 1024 molecules of O2 in your sample.
