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What is the mole fraction of O2 in the mixture 02?
It is 100%.
What is the composite of air?
Composition of air (% by volume):Nitrogen (N2): 78.09%Oxygen (O2): 20.95%Argon (Ar): 0.93%Carbon dioxide (CO2): 0.038%Others (less than 0.002% each): Neon (Ne), Helium (He), Krypton (Kr), Hydrogen (H2), Xenon (Xe).See the Related Links for "MIStupid.com: Composition of air" to the bottom for the answer.Our atmosphere also contains water vapor. In addition, Earth's atmosphere contains traces of dust particles, pollen, plant grains and other solid particles.
How many grams of O2 are in 15 moles of O2. with work shown?
To find the grams of O2 in 15 moles, we use the molar mass of O2, which is 32 g/mol. 15 moles x 32 g/mol = 480 grams of O2. Therefore, there are 480 grams of O2 in 15 moles of O2.
How do you figure out 3.2 moles of o2?
The mass of 3.2 moles O2? The atoms in 3.2 moles O2 Could be other things, I guess, but I will do these two. 3.2 moles O2 (32 grams/1 mole O2) = 102.4 grams of gaseous oxygen -------------------------------------------- 3.2 mole O2 (6.022 X 1023/1 mole O2) = 1.9 X 1024 atoms of gaseous oxygen --------------------------------------------------
How many grams are there in 2.047 moles of O2?
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
What mass of oxygen two moles of O2 molecules have molor mass of O2 is 32 grms per mole?
Two moles of O2 molecules would have a mass of 64 grams (2 moles x 32 grams/mole = 64 grams).
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
How you calculate the mass of 1.5 moles of oxygen molecule?
To calculate the mass of 1.5 moles of oxygen molecules (O2), you multiply the number of moles (1.5) by the molar mass of oxygen (O2). The molar mass of O2 is approximately 32 g/mol. So, the mass of 1.5 moles of oxygen molecules would be 1.5 moles * 32 g/mol = 48 grams.
Which best represents the number of moles in exactly 64 grams of oxygen (O2)?
The number of moles in exactly 64 grams of oxygen (O2) is two.
What is the number of molecules in 48.0 grams of oxygen gas O2?
The molar mass of O2 is 32 g/mol. To find the number of molecules in 48.0 grams of O2, we first need to find the number of moles using the formula: number of moles = mass / molar mass. Then, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
The number of molecules in 48.0 grams of oxygen gas (O2) is?
To find the number of molecules in 48.0 grams of oxygen gas (O2), you first need to determine the number of moles of O2 using its molar mass (32 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. The calculation would be: 48.0 g / 32 g/mol = 1.5 moles of O2, and 1.5 moles x 6.022 x 10^23 molecules/mol = 9.033 x 10^23 molecules of O2.
What is the weight in grams of 3 moles of diatomic oxygen?
The molar mass of diatomic oxygen (O2) is approximately 32 grams/mol. Therefore, 3 moles of diatomic oxygen would weigh 3 moles * 32 grams/mole = 96 grams.
How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
