There are 1.0001 moles.
Composition of air (% by volume):Nitrogen (N2): 78.09%Oxygen (O2): 20.95%Argon (Ar): 0.93%Carbon dioxide (CO2): 0.038%Others (less than 0.002% each): Neon (Ne), Helium (He), Krypton (Kr), Hydrogen (H2), Xenon (Xe).See the Related Links for "MIStupid.com: Composition of air" to the bottom for the answer.Our atmosphere also contains water vapor. In addition, Earth's atmosphere contains traces of dust particles, pollen, plant grains and other solid particles.
The partial pressure of a gas in a mixture is equal to the total pressure of the mixture multiplied by the mole fraction of that gas. Since the mole fraction of O2 in air is 0.2084 and the total pressure of air is approximately 1 atmosphere, the partial pressure of O2 in air is approximately 0.2084 atmosphere.
Moles of O2=2.5/32=0.078125 Moles of He=6.4/4=1.6 Mole fraction of O2=0.078125/(0.078125+1.6)=0.046555 Partial pressure of O2=0.046555 x 8.25=0.384atm
1 mole of O2 gas contains 2 oxygen atoms because each molecule of O2 consists of two oxygen atoms bonded together.
First calculate the moles of each gas using their molar masses (H2S = 34 g/mol, CH4 = 16 g/mol, O2 = 32 g/mol). Then find the total moles in the mixture. Lastly, divide the moles of H2S by the total moles to get the mole fraction of H2S in the mixture.
To find the mole fraction of nitric oxide, first calculate the moles of nitric oxide and oxygen gas separately by dividing the given mass by their respective molar masses. Then, find the total moles of both gases present in the mixture. Finally, divide the moles of nitric oxide by the total moles to calculate its mole fraction.
First, calculate the number of moles of each gas: 7.0 g H2S = 0.25 moles, 10.0 g CH4 = 0.28 moles, and 12.0 g O2 = 0.38 moles. Next, calculate the total moles of gas in the mixture: 0.25 + 0.28 + 0.38 = 0.91 moles. Finally, calculate the mole fraction of H2S: 0.25 moles H2S / 0.91 moles total = 0.275 or 27.5%.
The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.
1 mole of HgO produces 1 mole of O2 according to the balanced chemical equation for the reaction. Therefore, 0.440 moles of HgO will produce 0.440 moles of O2.
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
The balanced chemical equation for the reaction between magnesium and oxygen is 2Mg + O2 β 2MgO. It shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of Mg is 24.31 g/mol, and O2 is 32.00 g/mol. First, calculate the number of moles of O2 in 16g, then use the mole ratio from the balanced equation to find the moles of Mg, and finally convert to grams.
82.5 grams O2 (1 mole O2/32 grams)(6.022 X 10^23/1 mole O2) = 1.55 X 10^24 atoms of O2