Tenths (ie 1/10).
The 8 in 128.90 is in the place value column which is immediately before the decimal point - this is the ones column. The digit in 6.3457 which is in the ones place (immediately before the decimal point) is 6.
This is the decimal value 211. A binary number uses exponents of 2 rather than 10, and the 8 digits represent 128, 64, 32, 16, 8, 4, 2, and 1 11010011 = 128 + 64 + (0x32) + 16 + (0x8) + (0x4) + 2 + 1 = 211
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. So the required decimal representation is -992.
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. So the required decimal representation is 8410, as in the question.
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. If it does not contain a fractional part then the decimal representation does not require a decimal point. So the decimal for 8 oz is 8 oz – as in the question. If you want it as a decimal fraction of some other quantity then you need to specify that second quantity.
6.08712 8 hundredths
The last digit, 8, has a place value of ten thousandths. So take the number, remove the decimal point and divide by ten thousand. You can then simplify it, if required. 2048/10000 = 128/625
It is 4 digits right of the decimal, so it is the ten-thousandths place value.
8 and 6
an 8th of a decimal hundred
7.574
The 8 in 128.90 is in the place value column which is immediately before the decimal point - this is the ones column. The digit in 6.3457 which is in the ones place (immediately before the decimal point) is 6.
When writing binary numbers . . . The first place has the value of 1. The second place has the value of 2. The third place has the value of 4. The fourth place has the value of 8. '1 0 1 1 ' has (fourth place) + (second place) + (first place) = 8 + 2 + 1 = decimal 11 .
Conversion from Binary to Decimal is easy if you use this common method: Assign a decimal value to each place of the binary number starting with 1 at the right-hand digit. Double each decimal value going right to left <== for each remaining binary digit, 1's and 0's. Add up the decimal numbers that correspond to 1's in the binary number. 1, 1, 0, 1, 1, 0, 0, 1 binary 128, 64, 32, 16, 8, 4, 2, 1 = 128+64+16+8+1 = 217 decimal
8 and 6 respectively.
This is the decimal value 211. A binary number uses exponents of 2 rather than 10, and the 8 digits represent 128, 64, 32, 16, 8, 4, 2, and 1 11010011 = 128 + 64 + (0x32) + 16 + (0x8) + (0x4) + 2 + 1 = 211
This is the decimal value 181. A binary number uses exponents of 2 rather than 10, and the 8 digits represent 128, 64, 32, 16, 8, 4, 2, and 1 10110101 = 128 + (0x64) + 32 + 16 + (0x8) + 4 + (0x2) + 1 = 181