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What is the prime factorization of 1701 using exponents when repeated factors appear?
Updated: 4/28/2022
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∙ 11y agoBest Answer
35 x 7 = 1701
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∙ 11y agoThis answer is:
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Suppose you have a prime factor with an exponent of n. Then that prime factor can appear 0, 1, 2, ... , n times in a compound factor: that is, there are (n+1) different exponents that it can take.
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