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What is the prime factorization of 441 using exponents when repeated factors appear?
Updated: 4/28/2022
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What is the prime factorization of 1701 using exponents when repeated factors appear?
35 x 7 = 1701
What is the prime factorization of 792 using exponents when repeated factors appear?
23 x 32 x 11 = 792
What is the prime factorization of the number 1300 with exponents repeated factors appear?
22 x 52 x 13 = 1300
What is the prime factor of 1300 with exponents when repeated factors appear?
2^2 x 5^2 x 13
Why do you add 1 to each exponent after a number is factorized to determine the number of positive factors for any given number?
Suppose you have a prime factor with an exponent of n. Then that prime factor can appear 0, 1, 2, ... , n times in a compound factor: that is, there are (n+1) different exponents that it can take.
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What is the prime factorization of 196 using exponents when repeated factors appear?
22*72 = 196
What are the prime factorization of 245 using exponents when repeated factors appear?
245 = 51 x 72
What is the prime factorization of 1701 using exponents when repeated factors appear?
35 x 7 = 1701
What is the prime factorization of 4300 using exponents when repeated factors appear?
22*52*43 = 4300
What is the prime factorization of 75 using exponents when repeated factors appear?
75 = 3 x 52
What the prime factorization of 98 using exponents when repeated factors appear?
2 x 72 = 98
What are prime factorization of 36 using exponents when repeated factors appear?
22 x 32 = 36
What is the prime factorization of 792 using exponents when repeated factors appear?
23 x 32 x 11 = 792
What is the prime factorization of 1224 using exponents when repeated factors appear?
23 x 32 x 17 = 1224
What is the prime factorization of 936 using exponents when repeated factors appear?
936 = 23 x 32 x 13
What is the prime factorization of the number 1300 with exponents repeated factors appear?
22 x 52 x 13 = 1300
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