72 = 49
(98) = 2 * (49) = 7 * 7 ( both primes, end sequence) so > prime factors are : 21 * 72
42 and 48 2 x 3 x 7 = 42 24 x 3 = 48
The four factors of 343 are 1, 7, 49, and 343. The factor pairs of 343 are 1 x 343 and 7 x 49. The proper factors of 343 are 1, 7, and 49 or, if the definition you are using excludes 1, they are 7 and 49. The prime factors of 343 are 7, 7, and 7. The only distinct prime factor (listing each prime factor only once) of 343 is 7. The prime factorization of 343 is 7 x 7 x 7 or, in index form (in other words, using exponents) is 7^3.
The 6 factors of 147 are 1, 3, 7, 21, 49, and 147. The factor pairs of 147 are 1 x 147, 3 x 49, and 7 x 21. The prime factors of 147 and 3, 7, and 7. The prime factorization of 147 is 3 x 7 x 7 or, in index form (in other words, using exponents), 3 x 72.The prime factors of 147 are: 3 and 7
49 = 72
49 = 7^2
72 = 49
2 x 5^2 = 50
(98) = 2 * (49) = 7 * 7 ( both primes, end sequence) so > prime factors are : 21 * 72
49 7,7
It is: 7*7 = 49
7 x 7 = 49
what is the prime factorization of 49, 88,95,105,98,52,42,68,91,60,72,56,144,370,168,124,515,725,220,450,1000,1040,and 2500
Prime Factorization of 49 = 7x749 = 72
7 squared
The prime factorization of 49 is 7 x 7.