The prime factorization of 63 is 3 x 3 x 7 or 3^2*7 = 63
3 x 3 x 7 = 63
63 = 3 x 3 x 7
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The prime factors of 63 are: 3,7.3 x 3 x 7The prime numbers (factors) of 63 are: 3 and 73 and 73*3*7
63=3x3x7
The 6 factors of 63 are 1, 3, 7, 9, 21, and 63. The factor pairs of 63 are 1 x 63, 3 x 21, and 7 x 9. The proper factors of 63 are 1, 3, 7, 9, and 21; possibly not 1, depending on your definition. The prime factors of 63 are 3, 3, and 7. The 2 distinct prime factors of 63 are 3 and 7.
Sure thing, honey. To express 63 as a product of its prime factors, you break it down like this: 63 = 3 x 3 x 7. So, the prime factors of 63 are 3 and 7. That's all there is to it, darling.
The prime factors of 63 are 3*3*7 . The non-prime factors are 9 and 21. The multiples of 63 are 63 * n where n is any number you feel like. The second part of this question is essentially meaningless.