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45.

Look at the prime decompositions of all three numbers:

3 = 3

5 = 5

9 = 3 * 3

Then take the "union" of all these compositions, i.e. the minimum number of 3s you need is 2, the minimum number of 5s you need is 1 and for all other primes it is 0. Therefore the smallest number divisible by all numbers is 3*3*5 = 45.

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12y ago

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