16,17,18,19,20,21,22,23,24,25.
The ten numbers from 1 to 10.
The sum first Prime number is (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 ) = 129 The sum of the first composite numbers is (4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18) = 112 The difference is 129 - 112 = 17 !!!!!
There are infinitely many composite numbers. There are, therefore, infinitely many subsets of ten such numbers. There are, therefore, infinitely many possible sums.
4, 6, 8, 9, 10, 12, 14, 15, 16, 18
The numbers 4, 6, 8, 9, 10, 12, 14, 15, 16, 18 are the first ten composite numbers.
16,17,18,19,20,21,22,23,24,25.
The numbers 4, 6, 8, 9, 10, 12, 14, 15, 16, 18 are the first ten composite numbers.
2520
In other words, we require a sequence of consecutive numbers none of which are prime. This can be guaranteed if we obtain (10 + 1)! = 39916800 Then clearly, 39916800 + 2 is divisible by 2, 39916800 + 3 is divisible by 3, and so on to 39916800 + 11 is divisible by 11. Consequently, all ten numbers from 39916802 - 39916811 are composite.
4, 6, 8, 9, 10, 12, 14, 15, 16, 18 are the first ten composite numbers
12
composite numbers from one to ten: 4, 6, 8, 9, 10
A composite number is a number with more than two positive integer factors. As such, the first ten composite numbers are: 4, 6, 8, 9, 10, 12, 14, 15, 16, 18
nine, ten and eleven. Three consecutive numbers that total thirty
The ten numbers from 1 to 10.
18. The first ten composite numbers are: 4, 6, 8, 9, 10, 12, 14, 15, 16, 18