That 5 is a factor.
When adding and subtracting complex numbers, you can treat the "i" as any variable. For example, 5i + 3i = 8i, 5i -3i = 2i, etc.; (2 + 5i) - (3 - 3i) = (2 - 3) + (5 + 3)i = -1 + 8i.
Polar form = re^i(angle) r=(4+4)^.5 angle=atan(2/2) PF = (8)^.5*e^atan(1) pf = 2.83e^.7854i
Yes, a complex number can be graphed on a two-dimensional plane known as the complex plane. The real part of the complex number corresponds to the x-axis, while the imaginary part corresponds to the y-axis. The complex number is represented by a point in the complex plane, with its coordinates being the real and imaginary parts. The distance of the point from the origin represents the magnitude of the complex number.
2
That 5 is a factor.
0 + 5i Its complex conjugate is 0 - 5i
The conjugate of a complex number is the same number (but the imaginary part has opposite sign). e.g.: A=[5i - 2] --> A*=[-5i - 2] Graphically, as you change the sign, you also change the direction of that vector. The conjugate it's used to solve operations with complex numbers. When a complex number is multiplied by its conjugate, the product is a real number. e.g.: 5/(2-i) --> then you multiply and divide by the complex conjugate (2+i) and get the following: 5(2+i)/(2-i)(2+i)=(10+5i)/5=2+i
Use the Pythagorean theorem. 5, -5, 5i, and -5i will work, as well as any combination of a real and imaginary number such that (real part) squared + (imaginary part) squared = 25, for example, 4 + 3i, 3 + 4i, 4 - 3i, etc.
In the number: 5i, 5 is called the coefficient of i.
0.4
When adding and subtracting complex numbers, you can treat the "i" as any variable. For example, 5i + 3i = 8i, 5i -3i = 2i, etc.; (2 + 5i) - (3 - 3i) = (2 - 3) + (5 + 3)i = -1 + 8i.
5, -5, 5i, -5i, 5i^2, and many others... If you're asking this question, chances are it is either 5 or negative 5.
5√3 + 5i, -5√3 + 5i, -10i
Polar form = re^i(angle) r=(4+4)^.5 angle=atan(2/2) PF = (8)^.5*e^atan(1) pf = 2.83e^.7854i
5i
1/(2 + 5i) (multiply both the numerator and the denominator by 2 - 5i)= 1(2 - 5i)/(2 + 5i)(2 - 5i)= (2 - 5i)/(4 - 25i2) (substitute -1 for i2)= (2 - 5i)/(4 + 25)= (2 - 5i)/29= 2/29 - (5/29)i