60, 72, 84, 90 and 96
The maximum number of different factors is 12 and there are 5 numbers in 1-100 which have 12 factors.
No number under 100 has 13 factors. 60, 72, 84, 90, and 96 each have 12 factors.
60, 72, 84, 90, and 96 each have 12 factors.
Numbers that 6 factors 1-100: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96Numbers that have exactly 6 factors 1-100: 12, 18, 20, 28, 32, 44, 45, 50, 52, 63, 68, 75, 76, 92, 98, 99
60, 72, 84, 90 and 96 each have 12 factors.
The maximum number of different factors is 12 and there are 5 numbers in 1-100 which have 12 factors.
If it has an odd number of factors (greater than 3) then it must be a perfect square that is not the square of a prime number. This leaves 42, 62, 82 and 92. The answer is 82 = 64 which has the factors 64, 32, 16, 8, 4, 2 and 1.
-12 has twelve factors and is less than 100: -12,-6,-4,-3,-2,-1,1,2,3,4,6,12
21
25 it's factors are 1, 5,and 25. That's a number between 12 and 40 that has only 3 factors
No number under 100 has 13 factors. 60, 72, 84, 90, and 96 each have 12 factors.
60, 72, 84, 90 and 96 each have 12 factors.
60, 72, 84, 90, and 96 each have 12 factors.
Numbers that 6 factors 1-100: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96Numbers that have exactly 6 factors 1-100: 12, 18, 20, 28, 32, 44, 45, 50, 52, 63, 68, 75, 76, 92, 98, 99
To have an odd number of factors, the number must be a square. The only squares between 80 and 100 ()inclusive) are 81 and 100 but 81 does not have a factor of 5, and 100 has 9 factors. Thus the problem (as stated) has no solution. The numbers which have a factor of 5 must end in 0 or 5; the only numbers between 80 and 100 (inclusive) which match this criteria are {80, 85, 90, 95, 100}, which have {10, 4, 12, 4, 9} respectively. If you meant 3 PROPER factors (ie all the factors excluding the number itself), then 85 and 95 both have 3 proper factors.
12
60, 72, 84, 90 and 96 each have 12 factors.