To determine what number makes 371 divisible by 3, we need to sum the digits of 371: 3 + 7 + 1 = 11. To be divisible by 3, the sum of the digits must also be divisible by 3. Since 11 is not divisible by 3, we need to find the number that, when added to 11, results in a sum divisible by 3. The next multiple of 3 greater than 11 is 12, so the number that makes 371 divisible by 3 is 1.
211, since 201 and 207 is divisible by 3, 205 is divisible by 5, and 203 is divisble by 7, and 209 is divisible by 11. You can also use a complex algorithm of Ppi(200)+1, which gets 211 as well.
Yes, that is true.
as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...
15 is not a prime number because it is not only divisible by 1 and itself it is also divisible by 3.
NO, can 2 be divided by 6........ yes, can 4 be divided by 6......... Every number is divisible by every other number, but not always exactly. Not every number that is exactly divisible by 2 is exactly divisble by 4. Examples: 2, 18, 30, 46
No. In order for a number to be exactly divisible by 3, the digits in the number must also be divisible by three. In this example, 9+5+5=19.
No, it is an even number greater than 2 and is also divisible by 10. It is a composite number.
A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. A multiple factor is an oxymoron.
Four of them.
510
1, 2, 4, 5, and 10
Yes, any number that is divisible by 4 is also divisible by 2.
factors
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
It is divisible by their factors. It is also divisible by their product.
If a number is not divisible by 3 then it is not divisible by 9.