0
1 day=24_h_
1 hrs=60mins
1 day =(60x24)mins= 1440mins
So,℅of 18mins in day
18/1440x100=1.25
Alok Raj
aiman asim
Wiki User
∙ 7y ago18 minutes is 1.25% of one day.
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What percent of a day is 18 hours?
75% 18/24 x 100 = 75
What is 18 percent of 20000?
18 percent of 20000 is 3600.
18 percent of 5000?
We know that 18 percent of 100 is 18, and if you divide 5,000 by 100 you get 50. So multiply 18 x 50...So, 18 percent of 5000 = 900 We know that 18 percent of 100 is 18, and if you divide 5,000 by 100 you get 50. So multiply 18 x 50...So, 18 percent of 5000 = 900
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What percent of 1 day equals 18 minutes?
18 minutes equates to 1.25% of one day.
How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
How much of an 18 percent solution of sulfuric acid should be added to 360 ml of a 10 percent solution to obtain a 15 percent solution?
600ml.
What is 5 percent of 6 hours?
18 minutes
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How much pure acid is in 330 mL of a 18 percent acid solution?
18% of 330 = 59.4 So there are 59.3ml of pure acid in 330ml of 18% acid solution.
How many minutes are there in 18 days?
One day is equal to 60 x 24 = 1440 minutes. Therefore, 18 days is equal to 18 x 1440 = 25920 minutes.
What percent of a day is 18 hours?
75% 18/24 x 100 = 75
What fraction a day is 80 minutes?
It is: 80/(24*60) = 1/18 of a day
How many liters of 50 percent alcohol solution and 20 percent alcohol solution must be mixed to get obtain 18 liters of 30 percent alcohol solution?
The total volume of solution equals 18 L. So if we let X be the 50% solution & Y be the 20% solution we can solve a set of two equations with 2 unknowns: X + Y = 18 (total volume of solution is 18 L) 0.5X + 0.2Y = 18*(0.30) (the total amount of alcohol in the new 18L solution) Solving simultaneously, multiply the 1st equation by 0.5 then substract to solve for Y. X + Y = 18 {*0.5} => 0.5X + 0.5Y = 9 0.5X + 0.2Y = 5.4 => 0.5X + 0.2Y = 5.4 ------------------------------------------------------- 0.3Y = 3.6 Y = 12 Then substitute for Y back into the 1st equation & solve to get X=6. So you need 12 L of the 20% solution & 6 L of the 50% solutions to mix together to get 18 L of a 30% alcohol solution.
How many grams of NaCl are in 225 grams of an 18 percent NaCl solution?
The answer is 8 g NaCl.
How many liters of pure antifreeze must be added to 30L of 60 percent antifreeze solution to obtain a 75 percent solution?
60% solution contains 6/10 x 30 ie 18 litres 18 + A = 3/4 (30 + A) 72 + 4A = 90 + 3A 4A - 3A = 90 - 72 A = 18 ie add another 18 litres, giving 36 litres out of 48 which is the required 75%.
