Six twos.
These are the pairs of numbers that when multiplied are equal to 64: (1, 64) (2, 32) (4, 16) (8, 8)
The only prime factor of 64 is 2.
No, they are not relatively prime.
That's a false statement. Both 16 and 64 have one prime factor. 16 can't be the LCM of two prime numbers and 64 can't be the product. If you leave out the word prime, you can use 16 and 4.
The prime numbers are integers greater than 1 that have no positive divisors other than 1 and themselves. The prime numbers less than 64 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, and 61. Therefore, the prime numbers of 64 are 2 and 61.
8 times 8=64
There are not two prime numbers whose product is 64. The prime factorization of 64 is 2 x 2 x 2 x 2 x 2 x 2, which is 2 to the 6th power. These are the only prime numbers that can be multiplied together to result in 64. There are six of them, not two. The only pair of numbers whose product is 64 that includes one prime number is 2 x 32, but only one number is prime.
These are the pairs of numbers that when multiplied are equal to 64: (1, 64) (2, 32) (4, 16) (8, 8)
They both are not prime numbers
The only prime factor of 64 is 2.
The only prime factor of 64 is 2.
The sum of the prime numbers 11 and 53 equals 64.
2 x 2 x 2 x 2 x 2 x 2
64 has only one prime factor and it is 2
The only prime factor of 64 is 2.
You'll need six. 2 x 2 x 2 x 2 x 2 x 2 = 64
Yes, 64 can be a product of prime numbers. All integers are either prime numbers or a product of prime numbers (called the prime factorization of a number). The prime factorization of 64 is 2 x 2 x 2 x 2 x 2 x 2.