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Let's denote the two consecutive numbers as x and x+1. We can set up the equation x(x+1) = 2756. By expanding the left side of the equation, we get x^2 + x = 2756. Rearranging terms, we have x^2 + x - 2756 = 0. This is a quadratic equation that can be solved using factoring, the quadratic formula, or completing the square to find the two consecutive numbers.

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5mo ago

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n x (n + 1) = 2756

n2 + n - 2756 = 0

n = [-b ± (b2 - 4ac)½] ÷ 2a

= [-1 ± (1 + 4 x 2756)½] ÷ 2

= (-1 ± 11025½) ÷ 2

= (-1 ± 105) ÷ 2

= 104 ÷ 2 or -106 ÷ 2

= 52 or -53

So the two numbers are either (52 and 53) or (-53 and -52).

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Wiki User

12y ago
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8===>

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Wiki User

9y ago
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Q: What two consecutive numbers multiply to make 2756?
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