1290
15
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
51
-10 and -3
-1 and -120
The two numbers that multiply to make 40 and add to make -13 are -8 and -5. When you multiply -8 and -5, you get 40, and when you add them together, you get -13.
The numbers that multiply to make 84 and add to make 5 are 12 and -7. When you multiply 12 by -7, you get 84, and when you add them together, 12 + (-7) equals 5. Thus, the solution is 12 and -7.
-22
199
The numbers are: -5 and 3
-5 and +3
That depends whether you want to add the numbers, to multiply them, or what.
The two numbers that multiply to -15 and add up to 2 are 5 and -3. When you multiply 5 and -3, you get -15, and when you add them together, you get 2.
The two numbers that add to -11 and multiply to 19 are -10 and -1. When you add them together, -10 + (-1) equals -11. When you multiply them, -10 × -1 equals 10, not 19. Therefore, there are no two real numbers that satisfy both conditions simultaneously.
221
5 and -3
-5 and 3