If I understand the question correctly, you want the probability of each cube showing an odd number. If the number cubes are fair, then the answer is 1/4.
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In any range of numbers, the number of evens and odds can never be different by more than 1 . If you include the 572 and the 592, then that range includes 11 evens and 10 odds.
The Answer:We know the following properties of the parities concerning the numbers: odd + odd = eveneven + odd = odd (commutativity yields the vice verca possible too)even + even = evenThus, we know that the group of numbers have at least 1 odd. However, since 2 odds make an even, any amount of even amount of odds make an even. Therefore, there must be an odd number of odds (i.e., {1, 3, 5}, the only ones that exist in that set).QED.
Betting 20 on 20 to 2 odds, you will get a return of 200. The odds of 20 to 2 are equal to 10 to 1. For every 1 bet, you will get a return of 10. Bet 20, get a return of 20 x 10 or 200. Having the odds of 20 to 2 is very unusual because all legal betting venues would have changed such odds to read 10 to 1.
A long shot.
500. Since they alternate, half the numbers between 1 and 1000 are odd and the other half are even. Adding zero to the list does not change the number of odds.