The odds of rolling a 7 are 1/6. The odds of rolling two in a row are 1/36.
The odds of rolling an 11 are 1/18. The odds of rolling two in a row are 1/324.
The odds of rolling doubles are 1/6. The odds of rolling double twice in a row are 1/36.
Rolling 2 twice in a row in the first two rolls is 1/6*1/6 = 1/36. But rolling 2 twice eventually is as close to certainty as you can get.
The probability of rolling a 4 in a die is 1 in 6, or about 0.1667. The probability, then, of rolling a 4 in at least one of two dice rolls is twice that, or 2 in 6, or 0.3333. The probability of rolling a sum of 4 in two dice is 3 in 36, or 1 in 18, or about 0.05556.
In 2 rolls, it's 1/6 = 162/3% if you don't care what the number is.If you name the number you want before rolling, it's 1/36 = 27/9%.
The probability of rolling a sum of 8 on one roll of a pair of dice is 5/36.The probability of not rolling a sum of 8 on one roll of a pair of dice is 31/36.The probability of rolling a sum of 8 twice on two rolls of a pair of dice is(5/36)(5/36) = (5/36)2 .The probability of rolling first a sum of 8 and then rolling a sum that is not 8 on thesecond roll is (5/36)(31/36).The probability of rolling a sum that is not 8 on the first roll and rolling a sum of 8in the second roll is (31/36)(5/36).So The probability of rolling a sum of 8 at least one of two rolls of a pair of dice is(5/36)2 + (5/36)(31/38) + (31/36)(5/36) = 0.258487654... ≈ 25.8%.
Assuming that a dice roll is purely random, there is a 1 in 6 probability of landing on any number. Since the second roll depends on the probability of the first, they factor together: First Roll: 1/6 Second Roll: (1/6)(1/6) = 1/36 If you were rolling both dice at once, however, the math would be completely different.
1 in 12
That depends on whether you roll it twice or not...
The probability is 1/6.
one fourth
Rolling it once there is a 1 out of 6 chance - because there is 6 numbers on a dice and one of them is three. so rolling it twice would be a 2 out of 12 chance / 0.16 / 16% chance
Rolling 2 twice in a row in the first two rolls is 1/6*1/6 = 1/36. But rolling 2 twice eventually is as close to certainty as you can get.
I'm going to assume you mean rolling the same number twice in a row in 25 rolls. The first won't cause a double, so you just need to consider the odds of rolling the same number as the last for the last 24 rolls. The easier approach is to realize that the probability of rolling at least one double is 1 minus the probability of rolling no doubles. One roll has this probability of not rolling the same as the last: P(different number from last) = 5/6 Since they are independent events: P(no doubles in 25 rolls) = (5/6)24 Now the final probability, of at least one double, is 1 - (5/6)24
The chance of rolling a 6 twice in a row, on a six-sided die, is 1 in 36 or 2.78%. The number of possible different results for rolling a six-sided die twice is 6 squared (6 times 6), or 36, therefore the probability of getting any one of the possible results is 1 out of 36.
The probability of rolling 7 once with two dice is 1 in 6, o 0.1667. The probability, then, of doing that twice in a row is 1 in 36, or 0.02778.
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
There are 6X6 or 36 combinations; and you can get a 1 & 6 twice; so the answer is 2/36 or 1/18.
It is 1/36.