234
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For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
The greatest common factor of 123 and 234 is 3.123: the digits (1, 2, 3) add up to 6.234: the digits (2, 3, 4) add up to 9.So both 6 and 9 are divisible by three.More formally:The prime factors of 123 are 3 and 41, while the prime factors of 234 are 2, 3, 3, and 13. The intersection of [3, 41] and [2, 3, 3, 13] is [3], therefore the Greatest Common Factor (GCF) of 123 and 234 is 3.
You test by := All EVEN Numbers are divisible by '2' All numbers ending in '5' or ''0' are divisible by '5' All numbers whose digits add to '9' are divisible by '9'. e.g. 234 2+3+4 = 9 All numbers whose form is ' m(m+n)n ' e.g. 132 are divisible by '11'. This leaves only '3' and '7' to test by actual division.
Oh, dude, let me drop some math knowledge on you. So, a prime number is a number greater than 1 that can only be divided by 1 and itself. Out of those options, 563 is the only prime number. The rest are just hanging out, being all divisible and stuff.
The common multiples of 3 and 9 are 9, 18, 27 and so on.Any number that is divisible by 9 is also divisible by 3. This is because 9 is divisible by 3, so any multiples of 9 must also be divisible by three.78 117 156 195 234 273 312 351 390and so on ...