234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
All even numbers (they end in 0,2,4,6 or 8) are divisible by 2
78, 156, 234 and so on.
1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
234 is an even number so it is divisible by 2.
234
234 is divisible by: 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117 and 234.
All even numbers (they end in 0,2,4,6 or 8) are divisible by 2
78, 156, 234 and so on.
1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, 234
i don't know help
234 is even and divisible by three. It has to be divisible by 6.
234 is an even number so it is divisible by 2.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.
Yes: 3 x 78 = 234
Any element of the set of numbers of the form 78*k where k is an integer.
For any larger number for which you have to test divisibility, split this factor up into smaller numbers. For example, you know that 2340 is divisible by 90 because you can divide it by 10 (2340 / 10 = 234), and then you can divide 234 by 9 (234 / 9 = 26).