No multiples of the same number greater than one can be co-prime, since they will both have that number as a factor.
which two multiples of 13 are co-prime numbers
Since both 11 and 13 are prime numbers, the LCM of these 2 number is 11 * 13 = 143. All multiples of 143 are multiples of 11 and 13 as well
13 is a prime number, which means the only multiple of the number is 1.
There is an infinite number of common multiples for 12 and 13, and each is a multiple of the LCM of 12 and 13, which is 156, 312, 468, 624, 780, 936, and so on.
13 is a prime number. 13, like every other prime number, has only two factors. The factors of 13 are 1 and 13. Any multiple of any number greater than one would have at least three factors: 1, the number, and the number it is a multiple of.
As many as you like because 13 is a prime number in its own right
Since the numbers are coprime, the answer is 21*13 = 273.
There is an infinite number of common multiples for 13 and 17. A common multiple of any two numbers is any number into which each of two or more number can be divided with zero remainder.
There is an infinite number of common multiples for 13 and 18. A common multiple of any two numbers is any number into which each of two or more numbers can be divided evenly (zero remainder).
There is an infinite number of common multiples for 13 and 22. A common multiple of any two numbers is any number into which each of two or more numbers can be divided evenly (zero remainder).
13
Two multiples of any number greater than one can't be co-prime. They would always have that number as a common factor.
No.
13 and all its multiples are divisible by 13.
There is an infinite number of common multiples for 13 and 81. A common multiple of any two or more numbers is any number into which each of two or more numbers can be divided evenly (zero remainder). However, the least or lowest common multiple of 13 and 81 is 1,053.
If you are talking about factors, there is only the number 1, because 13 is a prime number. If you are talking about multiples, then there are an infinite number of multiples (e.g. 50 x 13 = 650).
This is a nonsensical question. There are more than 13 multiples of 10 - in fact there are an infinite number. And there are multiples of 10 which have an infinite number of factors - so there cannot be a "largest" number of factors.
Since both 11 and 13 are prime numbers, the LCM of these 2 number is 11 * 13 = 143. All multiples of 143 are multiples of 11 and 13 as well