Multiples of 13, like 13, 26 and 39.
Multiples of 13 have 13 as a factor. 13, 26, 39 and so on.
The prime numbers: 2, 3, 5, 7, 11, 13, 17, 19
'26' has only two factors, they are '2' & '13' ; 2 x 13 = 26 or 13 x 2 = 26 Both '2' and '13' are prime numbers.
The multiples of 13 are numbers that can be divided by 13 without leaving a remainder. The multiples of 13 are: 13, 26, 39, 52, 65, 78, 91, 104, 117, and so on. The multiples of 7 are numbers that can be divided by 7 without leaving a remainder. The multiples of 7 are: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, and so on.
No multiples of the same number greater than one can be co-prime, since they will both have that number as a factor.
It can be. Since 13 is a prime number, it is relatively prime to all other numbers except for multiples of 13.
Since both 11 and 13 are prime numbers, the LCM of these 2 number is 11 * 13 = 143. All multiples of 143 are multiples of 11 and 13 as well
Themselves and their multiples because 17 and 13 are both prime numbers.
The prime numbers between 13 and 28 are 13 17 19 23 Multiples of 7 in that range include 14, 21 and 28.
The LCM of the given prime numbers is 39
Oh, dude, you're hitting me with the math questions? Alright, so technically, there are infinite prime multiples of 13 because any multiple of 13 that is greater than 13 itself will be a prime multiple. So, like, you can keep going and going with those bad boys. But let's be real, who's got time to count all those? Just know they're out there, living their best prime multiple lives.
There are two prime numbers that equals 50. The two numbers are 13 & 37. Both numbers are prime, so that's the answer.
13*31=403 13 and 31 are prime numbers.
If they have a Prime multiple in common, then they are not co-prime numbers.Hence no 2 multiples of 13 exists to satisfy this condition.
39 is the product when the two prime numbers 3 and 13 are multiplied.
The two proper prime factors are 7 and 13.