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I believe it is because 0 does not have an inverse element.

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Q: Why are the rational numbers under the operation of multiplication not a group?
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Is the set of rational numbers a commutative group under the operation of division?

No, it is not.


Why the set of rationals does not form a group wrt multiplication?

All the elements in a group must be invertible with respect to the operation. The element 0, which belongs to the set does not have an inverse wrt multiplication.


What group of real numbers will 9.34 go to?

A group containing 9.34 is a set of numbers, with some operation defined on the set that also satisfies:closure,associativity,identity, andinvertibility.Two simple groups will be the additive group of 9.34 and all its multiples (including negative ones). The identity is 0.The other is the multiplicative group consisting of all powers of 9.34 and the identity is 1.There can be a finite additive group derived from the first by defining the operation as modulo addition, and similarly with the multiplicative group.Finally, any group that contains one of these groups and also maintains the four conditions listed above, for example, all rational numbers, will also meet the requirements.


Are integers always sometimes or never rational numbers?

All integers are rational numbers, but not all rational numbers are integers.2/1 = 2 is an integer1/2 is not an integerRational numbers are sometimesintegers.


What do rational numbers look like?

Any fraction with integers in the numerator and in the denominator is a rational number.If you write them as decimals, a rational number will either terminate, or the same group of digits will repeat forever, as in 0.33333... or 2.174646464646...