Let's start with an example:
1/2 + 1/3
To add these two fractions, you first need to find the LCM which here is 6
Then you change both denominators to 6 and the problem becomes 3/6 + 2/6 = 5/6
Now if the LCM were 0, then you would get a denominator, 0. But you can not divide by 0. It becomes meaningless.
So the LCM always excludes 0
Shell program to find LCM and hcf of two no.s tput clear echo "Enter first no" read a echo "Enter 2nd no" read b p= 'expr $a \* $b' while [$b -ne 0] do r= 'expr $a % $b' a=$b b=$r done LCM = 'expr $p / $a' echo "LCM = $LCM" echo "Hcf = $a"
The LCM is a concept that makes sense for a set of non-zero integers. Otherwise, 0 is always the LCM of any set of numbers - even if none of them is 0.
Yes. If a x b = 0 then either a = 0, b = 0, or a = b = 0.
No.-------------------------------------------------------------To find the HCF and LCM of two (or more) numbers list the numbers in their prime factorisations in power format; then:HCF = product of the primes to the LOWEST power across all the numbers;LCM = product of the primes to the HIGHEST power across all the numbers.Note: for p being any prime, p⁰ = 1; so if a prime does not appear as a factor of a number, it can be said to have a power of 0. This means that the LOWEST power is 0 and the prime does not appear in the HCF of the numbers. The HIGHEST power of a prime must be at least the LOWEST power of a prime.Thus if a prime appears in the HCF of the numbers (with a power greater than or equal to 1) it MUST also appear in the LCM of the numbers.If the HCF of some numbers is 15, then: 15 = 3 × 5 which means that the primes 3 and 5 MUST both apear in the LCM.But 175 = 5² × 7, which does NOT include 3, so 175 CANNOT be the LCM of some numbers which have a HCF of 15.
Least common multiple (LCM) is the is the multiple of the highest power of prime factors in the given numbers. For example, LCM of 4, 8, and 12 = 23 x 3 = 8 x 3 = 24.The LCM is the smallest number that each of your given numbers will go into. So, 4 will divide into 12 but 8 won't. If you're not comfortable with prime numbers, which is the best way to approach this problem, try stepping up one each time. 12 x 2 = 24. 4 will divide into 24 and so will 8. So 24 is the LCM of those three numbers.The LCM, or least common multiple, is the smallest positive whole number exactly divisible by two or more given whole numbers. Example: the LCM of 14 and 35 is 70 because 70/14=5 and 70/35=2, and no number smaller than 70 is exactly divisible by 14 and 35.LCM is Lowest Common Multiple or Least Common Multiple.It is the Lowest (whole) number (greater than 0) that is a multiple of all the other (whole) numbers.It is sometimes referred to as the LCD or Lowest Common Denominator when dealing with fractions and trying to find the (lowest) denominator to use for equivalent fractions (so that all the fractions have the same denominator for addition or subtraction of the fractions). By using the LCM of the denominators it keeps the numerators of the equivalent fractions as small as possible.
#include<stdio.h> main() { int a,b,i,lcm,gcf; printf("\n Enter two numbers"); scanf("%d%d",&a,&b); for(i=0;i<=a;i++) { if((b%i==0)&&(a%i==0)) { gcf=i; } } lcm=a*b/gcf; printf("\n GCF is %d and LCM is %d",gcf,lcm); }
As a general principle, you can find the LCM of two numbers by dividing their product by their GCF. This one won't work. The product of any two numbers with 5 as a common factor would have to end in 5 or 0.
The LCM is not defined for any set of numbers that contains a zero.
Shell program to find LCM and hcf of two no.s tput clear echo "Enter first no" read a echo "Enter 2nd no" read b p= 'expr $a \* $b' while [$b -ne 0] do r= 'expr $a % $b' a=$b b=$r done LCM = 'expr $p / $a' echo "LCM = $LCM" echo "Hcf = $a"
#include<stdio.h> #include<conio.h> void lcm(int m,int n) { for(i=1;i++) { if(i%m==0&&i%n==0) return i; } } void main() { clrscr(); int a,b; a=19;b=20; printf("lcm is %d",lcm(a,b)); getch(); }
You can compare them by looking at them (they are the same)subtracting one from the other (answer = 0)dividing one by the other (the quotient is 1).
Because the LCM has to be a multiple of both numbers. A number can't have a multiple smaller than itself.
The LCM is a concept that makes sense for a set of non-zero integers. Otherwise, 0 is always the LCM of any set of numbers - even if none of them is 0.
Least common multiples do not use zero as a multiple, as the LCM for any number and zero is zero.
#include<stdio.h> #include<conio.h> void main() { int x,y,z,i; clrscr(); printf("Enter Two Numbers = "); scanf("d%d",&x,&y); for(i=1;i<=x*y*z;i++) { if(i%x==0&&i%y==0) { printf("LCM is %d\n",i); break; } } getch(); }
Yes. If a x b = 0 then either a = 0, b = 0, or a = b = 0.
The LCM of any two numbers can be found with the following formula:LCM(a,b) = (ab) / GCD (a,b).The GCD of two numbers is best found with the Euclidean algorithm which is as follows:GCD(a,b) =a --if b = 0or GCD(b, a mod b) otherwiseIn the example given we have GCD(42,7) = GCD(7, 0) = 7Then LCM(42,7) = (7*42)/7 = 42Note: mod is the operation of dividing one number by another and taking the remainder. e.g. 7 mod 4 = 3, 12 mod 6 = 0.