Factor trees are useful to see all of the factors of a number. If you end up with a composite, or un-Prime number, you havent successfully completed the factor tree.
for example:
50
10,5
you obviously wouldn't end here because you can break 10 down into 5 and 2
you finished tree would look like
50
10,5
5,5,2
To find the highest prime factor of 420, we first need to factorize 420 into its prime factors. 420 can be expressed as 2^2 * 3 * 5 * 7. The highest prime factor is 7. Prime factors are numbers that can only be divided by 1 and themselves without leaving a remainder, and the highest prime factor is the largest prime number that can divide the original number.
To find the largest odd natural number that is a factor of 120, we first need to factorize 120 into its prime factors, which are 2^3 * 3 * 5. Since we are looking for an odd factor, we can ignore the factor of 2. The largest odd factor of 120 is then 3, as it is the largest odd prime factor present in the prime factorization of 120.
Two (or more) numbers are said to be co-prime if they have no prime factor in common. The numbers, themselves need not be prime. Thus, 14 (= 2*7) and 15 (= 3*5) are co-prime.
A factor tree will show you the prime factorization of 88. Comparing that prime factorization of 88 and another number will you show you the GCF between the two. You need at least two numbers to find a GCF.
Divide the number by it's lowest prime factor possible continuosly until you get a one. The numbers will then be the prime factors. For example: Take the number 66. 2 is the smallest prime number and it is a factor of 64. So 66/2 = 33. 33 is not divisible by 2 so we take the next lowest prime factor: 33/3 = 11. 11 is divisible by nothing but itself and so 11 is the next lowest prime factor (remember we always need the answer to remain an integer): 11/11 = 1. Therefore 66 = 2 x 3 x 11.
You need to factor it, into prime factors. Then, for every prime factor that appears an ODD number of times, you need to multiply 2306 by this prime factor. Multiply all such prime factors together to get your answer.
37 is already prime. No need for a tree.
19 is already prime; no need for a tree.
No. If the number has one factor (other than 1 and itself) it is a composite. However, to establish that a number is prime it needs to be checked for divisibility by each prime number up to the square root of the number. If the only factor found is 1, then it is a prime.
GCF of a prime number and a composite number is 1 if the prime number is not a factor of the composite number. Here 103 is a prime number and 120 is a composite number. And 120 is not divisible by 103(or 103 is not a factor of 120). So, GCF(103,120) = 1
13 is already prime. It doesn't need a tree.
To find the highest prime factor of 420, we first need to factorize 420 into its prime factors. 420 can be expressed as 2^2 * 3 * 5 * 7. The highest prime factor is 7. Prime factors are numbers that can only be divided by 1 and themselves without leaving a remainder, and the highest prime factor is the largest prime number that can divide the original number.
The prime factors of 110 are 2, 5 and 11. For them to be common, they need to be compared to another set of prime factors.
The prime factors of 6 are 2 and 3. For them to be common, they need to be compared to another set of prime factors.
All composite numbers can be expressed as unique products of prime numbers. This is accomplished by dividing the original number and its factors by prime numbers until all the factors are prime. A factor tree can help you visualize this. Example: 210 210 Divide by two. 105,2 Divide by three. 35,3,2 Divide by five. 7,5,3,2 Stop. All the factors are prime. 2 x 3 x 5 x 7 = 210 That's the prime factorization of 210. The largest of those numbers is the largest prime factor.
To know that a number is prime you need to know that it has no factors other than 1 and the number itself.To know that a number is composite you only need to know one factor other than the number itself or 1.
To find the largest odd natural number that is a factor of 120, we first need to factorize 120 into its prime factors, which are 2^3 * 3 * 5. Since we are looking for an odd factor, we can ignore the factor of 2. The largest odd factor of 120 is then 3, as it is the largest odd prime factor present in the prime factorization of 120.