Whether or not it is difficult depends on your aptitude and your attitude. What you may find difficult I might find easy and conversely.
960 The easiest way to work out a percentage of something, is to convert the percentage into a decimal. 20% can also be written as 0.2 as a decimal. You can then multiply 4800 by 0.2. This works with any number as well. When the percentage is more difficult and you do not have a calculator, you can work out 10%, and then multiply that answer by 2 (to get 20%) Hope this helped :D
You simply use more binary digits.
Oh, dude, the BCD number system is like that old-school friend who still uses a flip phone. The advantage is it's easy for humans to read since each decimal digit is represented by a 4-bit binary number. But the downside is it's not very efficient in terms of storage space compared to other number systems. So, like, it's great for nostalgia but not so much for modern computing efficiency.
You convert 98 base 10 into 1100010 base 2 the same way you convert any decimal number into a binary number. You iteratively divide by 2, recording the remainders in reverse order, until the quotient is zero.98 / 2 = 49 remainder 049 / 2 = 24 remainder 124 / 2 = 12 remainder 012 / 2 = 6 remainder 06 / 2 = 3 remainder 03 / 2 = 1 remainder 11 / 2 = 0 remainder 1So the result, reading backwards (up) is 1100010 base 2.and as an 8 bit value it would be 01100010.The more general answer is that, to convert a number in any base to any other base, iteratively divide the first number by the second base, using the rules of arithmetic of the first base, recording the remainders in reverse order, until the quotient is zero. The remainders then need to be written in terms of the second base.
There can be no number that has more than one decimal point.
As compared to converting decimal into what other base! It is no more difficult to convert decimal into base 8 than decimal into binary or Hex.
The answer depends on what the comparison is with! It is not more difficult than proving the Goldbach conjecture, for example.
HI use the following link http://cs.furman.edu/digitaldomain/more/ch6/dec_frac_to_bin.htm
HI use the following link http://cs.furman.edu/digitaldomain/more/ch6/dec_frac_to_bin.htm
How is this a question? Sounds like you should do more of your homework offline.
100, 104.858, or 95.367, depending on if you mean decimal to decimal, binary to binary, decimal to binary, or binary to decimal. Simply, decimal megabytes, used by the storage industry, is 1,000KB, where each KB is 1,000 bytes. Binary megabytes, used by programmers (such as Microsoft, Linux, etc) are 1,024 KB, where each KB is 1,024 bytes (2^10, or 0x0200). Converting from decimal to binary will yield a smaller number of megabytes, while converting from binary to decimal will result in more megabytes.
Good grief! We can't even write out a googolplex in decimal! How are you going to write it out in binary?
4095 For anything more complex I would use the standard 'calculator' provided with Windows, click on 'View' then 'Scientific'. The radio buttons let you select Decimal, Hex, Octal or Binary for the currently displayed number.
In binary: 11.00100100001111110110 In Decimal: 3.14159265358979323846 In hexadecimal: 3.243F6A8885A308D31319
If you mean a straight forward algorithm, then yes.I guess you want to know what it is...Start at the left hand end of the binary number with the result (decimal number) set to zerodouble the result and add the current binary digitif there are more binary digits move one binary digit to the right and repeat step 2repeat steps 2 and 3 until all the binary digits have been used.the result is the decimal equivalentfor example converting 101002 to decimal:1. set result to 0, start with the first binary digit (of 10100) which is 12. 2 x 0 + 1 = 13. 2nd binary digit (of 10100) is 02. 2 x 1 + 0 = 23. 3rd binary digit (of 10100) is 12. 2 x 2 + 1 = 53. 4th binary digit (of 10100) is 02. 2 x 5 + 0 = 103. 5th binary digit (of 10100) is 02. 2 x 10 + 0 = 203. no more binary digits4. 101002 = 2010
Just separate all the numbers in groups of four look (1011101.01101100)2 to hexa 0101 1101. 0110 1100 Then replace the binary numbers for hexa numbers 01012= 516 11012=D16 01102=616 11002=C16 so (1011101.01101100)2 = (5D.6C)16
For the simple reason that the 'places' in a binary number represent multiples of 2, rather than 10. Therefore, a binary '10' = a decimal '2.'