Lets investigate.
To find an LCM you do a prime factorization and choose the factors, which are not in common raised to an appropriate power to show how many times it occurs in one of the 2 numbers AND use all factors that they do not have in common also to an approp. power.
Ex 1 LCM of 49 and 25
prime factorization yields 5x5 and 7x7
SO LCM will be (5x5)x(7x7) because they have no common factors
which equals 352
Ex 2 LCM of 100 and 36
prime factorization yields 5x5x2x2 and 3x3x2x2
They have common factors of 2x2 so use these but dont repeat them
So LCM = (5x5)x(3x3)x(2x2) = (5x3x2)x(5x3x2) = 302
So every square (A) when factored becomes either (a x a) or (b x b x c x c) etc.
Lets find the LCM of A and N where A and N are squares, but not equal.
Prime factorization A = ( a x a x b x b) and N = ( n x n x p x p x a x a)
LCM will equal (b x b) x ( n x n x p x p) x (a x a) <-- common factors
= (a x b x n x p) x (a x b x n x p)
= (a x b x n x p)2 which is a square.
The rules for forming a LCM force you to make a square because each original number has a prime factorization that has 2 factors, and you must use both or you will not form a LCM.
No, but only in the case of the number 1 (12=1) are square numbers odd.
True.
No. The square of an odd number will be odd and the square of an even number will be even.Examples:5x5=2511x11=12115x15=2254x4=168x8=6416x16=256
The square root of a composite number is not always an irrational number. e.g. 4 is a composite number and its square root is 41/2 = 2, which is rational number.
There are infinitely many possible answers. The smallest set of numbers is (9, 16, 144, 169)
Yes
That's the "square" of the number. With counting numbers, the square will always be another counting number.
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=== === No === ===
when you subtract one square number with another the answer is 16 what are the two numbers
4 and 9
The square numbers are: 16-4 = 12
Another square number.
all of the numbers, except the numbers 1 and below
No, but only in the case of the number 1 (12=1) are square numbers odd.
No, and I can prove it: -- The product of two rational numbers is always a rational number. -- If the two numbers happen to be the same number, then it's the square root of their product. -- Remember ... the product of two rational numbers is always a rational number. -- So the square of a rational number is always a rational number. -- So the square root of an irrational number can't be a rational number (because its square would be rational etc.).
16 and 4