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What is the sum of 3256 and 4098 rounded to the nearest hundred?
3300
When the 3 digit number is rounded to the nearest hundred it rounds to 200 rounded to the nearest ten this number rounds to 200 the sum of the digits is 19 what is the number?
199
If the sum of a two digit number is 12 and the digits interchange their places the new number exceeds the original number by 25 what is the product?
-- "The sum of a two-digit number" is unclear. I took it to mean"The sum of the digits of a two-digit number."-- "... the product ?" is unclear. Are you looking for the product of the two digits,or the product of the forward and backward numbers ?-- It's not possible to write a number whose two digits sum to 12 and whosereverse exceeds it by 25. The tens digit would have to be 4.611... and the unitsdigit would have to be 7.388... .Then(4.611...) + (7.388...) = 12(46.111...) + (7.388...) = 53.5(73.888...) + (4.611...) = 78.5Difference = 25So, the number can't be written, but ...The product of its two digits is 34.071 (rounded)The product of the forward and reverse numbers is 4,199.75 (rounded)
You are a 4 digit number the sum of your four digit is 28 three of your digits are the same whether you are rounded to the nearest tenth hundredth or thousand you are still the same number?
Any whole number will stay the same when rounded to any decimal place. 4888, 8488, 8848, 8884, 1999, 9199, 9919, 9991 would all qualify.
When this 3 dig numbers is rounded to the nearest ten the sum of its digits is 16 the hundreds digit of this number is 8 and the ones digit is 5 what is the number?
875
