WRITE A PROGRAM TO CONVERT A 2-DIGIT bcd NUMBER INTO HEXADECIMAL
jump,b
The same way you would in a regular java program. int i = 10; String s = i + ""; after the above line of code the variable s will have "10" as a string value...
If you are typing the numbers into a computer program or a calculator, just type them, such as 12345678. If you are writing them down for someone else to read them, then you should group them in three's, from the decimal point, such as 12,345,678. Depending on the normal conventions for your country, you might use a period instead of a comma and, for the decimal point, a comma instead of a period.
10.INPUT "ENTER TEMPERATURE IN FAHRENHEIT " ;F 20.LET C =5/9*(F-32) 30.PRINT "TEMPERATURE IN CENTIGRADE " ;C 40.END With This Above Program You Can Convert Cent Temp Into Far Temp.... R U Happy Now for More......Contact At syedalibukhari386@yahoo.com Bukhari386
This is not a question.
pongada punda vayanungala ..................
Write a program to convert a 2-digit BCD number into hexadecimal
WRITE A PROGRAM TO CONVERT A 2-DIGIT bcd NUMBER INTO HEXADECIMAL
Write a program to convert a 2-digit BCD number into hexadecimal
In order to convert binary to hexadecimal using assembly language, the programmer must possess an understanding on boolean algebra or binary system in other words. A compiler is also needed to complete the program.
write a c++ program to convert binary number to decimal number by using while statement
jump,b
The question asks to do nothing by converting a decimal into itself. Perhaps the question was mistyped. Please restate the question.
To input a decimal number and display in hex, something like: char buffer[99]; fgets(buffer, 98, stdin); printf("%x", aoti(buffer)); would be the required core code. Needless to say, there is no error checking, mug trapping, etc. Or if you require the hex in a char[], then replace "printf(" by "sprintf(pointer_to_bufffer,"
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
Use the %X modifier of printf.Code Example:#include int main(void) { unsigned int iMyNumber = 255; printf("The number %u interpreted as hexadecimal is %X.\n", iMyNumber, iMyNumber); return 0; }