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If y varies inversely as the square of x and y equals 4 when x equals 3 find y when x is 2?
y varies as 1/x^(2) y = k X 1/^(2) y = k/x^(2) k = y x^(2) When y = 4 & x = 3 Then k = 4(3^(2)) k = 4(9) k = 36 (The constant of proportionality Hence the general equation is y = 36/x^(2) When x = 2 y = 36/2^(2) y = 36 /4 y = 9 The answer!!!!!
If y Varies Directly as x to the 2nd power and y equals 198 when x equals 6 find y when x equals 2?
y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22
What is the y intercept of 2x plus 6y equals 36?
A line intercepts the y axis when x=0. If we put x=0 into the equation we get 2x0 + 6y = 36 6y = 36 y = 6 (dividing both sides by 6) Thus the line intercepts the y axis when x is 0 and y is 6. This is the point with the coordinates (0,6)
How do you solve 6y2-36 equals 6y?
6y2 - 36 = 6ySubtract 6y from each side:6y2 - 6y - 36 = 0Divide each side by 6:y2 - y - 6 = 0Factor the expression on the left side:(y + 2) (y - 3) = 0The equation is a true statement if either factor is = 0.y + 2 = 0 ==> y = -2y - 3 = 0 ==> y = 3
If 5y 8 37 then y 4?
36
