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5y - 4 plus 3y equals 12?
5y - 4 + 3y = 12 Combine like terms: 8y - 4 = 12 Add 4 to both sides: 8y = 16 Divide both sides by 8: y = 2
What does 6-y plus 5y-6y?
6 - y + 5y - 6y = 0 6 = y -5y + 6y 6 = -4y + 6y 6 = 2y 6/2 = y 3 = y
What are the solutions to the simultaneous equations of x -2y equals 1 and 3xy -y2 equals 8?
If: x-2y = 1 then x = 2y+1 If: 3xy -y^2 = 8 then 3*(2y+1)*y -y^2 = 8 So: 6y^2 +3y -y^2 = 8 or 5y^2 +3y -8 = 0 Factorizing the above: (y-1)(5y+8) = 0 meaning y = 1 or y = -8/5 Solutions by substitution are: (3, 1) and (-11/5, -8/5)
What is the x intercept of -5y plus 3x equals 12?
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
What are the solutions to the simultaneous equations of 3xy -y squared equals 8 and x -2y equals 1?
The two equations are: 1) 3xy - y² = 8 2) x - 2y = 1 Make x the subject of (2): x - 2y = 1 → x = 2y + 1 substitute for x in (1) and solve for y: 3xy - y² = 8 → 3(2y + 1)y - y² = 8 → 6y + 3y - y² - 8 = 0 → 5y + 3y - 8 = 0 → (5y + 8)(y - 1) = 0 → 5y + 8 = 0 → y = -8/5 or y - 1 = 0 → y = 1 and substitute into 2 to find the corresponding x: y = -8/5 → x = 2(-8/5) + 1 = -11/5 y = 1 → x = 2(1) + 1 = 3 → the solutions are the ordered pairs (-11/5, -8/5) {or (-2.2, -1.6)} and (3, 1)
