5y - 4 + 3y = 12 Combine like terms: 8y - 4 = 12 Add 4 to both sides: 8y = 16 Divide both sides by 8: y = 2
6 - y + 5y - 6y = 0 6 = y -5y + 6y 6 = -4y + 6y 6 = 2y 6/2 = y 3 = y
If: x-2y = 1 then x = 2y+1 If: 3xy -y^2 = 8 then 3*(2y+1)*y -y^2 = 8 So: 6y^2 +3y -y^2 = 8 or 5y^2 +3y -8 = 0 Factorizing the above: (y-1)(5y+8) = 0 meaning y = 1 or y = -8/5 Solutions by substitution are: (3, 1) and (-11/5, -8/5)
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
The two equations are: 1) 3xy - y² = 8 2) x - 2y = 1 Make x the subject of (2): x - 2y = 1 → x = 2y + 1 substitute for x in (1) and solve for y: 3xy - y² = 8 → 3(2y + 1)y - y² = 8 → 6y + 3y - y² - 8 = 0 → 5y + 3y - 8 = 0 → (5y + 8)(y - 1) = 0 → 5y + 8 = 0 → y = -8/5 or y - 1 = 0 → y = 1 and substitute into 2 to find the corresponding x: y = -8/5 → x = 2(-8/5) + 1 = -11/5 y = 1 → x = 2(1) + 1 = 3 → the solutions are the ordered pairs (-11/5, -8/5) {or (-2.2, -1.6)} and (3, 1)
I assume you mean find Y and then add it to 4. 5Y - 8 = 37 add 8 to each side 5Y = 45 divide both sides by 5 Y = 9 ( it checks by inspection; so....) 9 + 4 = 13
8 - 5y = 12 -5y = 4 y = -4/5
8+y = 7+5y y-5y = 7-8 -4y = -1 y = 1/4
5y+8=7y subtract 5y from each side , 5y+8=7y -5y -5y 8=2y /2 /2 4=y
5y+8=7y 2y=8 y=4
8 + 5y = 18 Therefore, 5y = 10 y = 10/5 y = 2
f(x)= (4 - 5y)/8 f(y)= (4 - 8x)/5
5y-8 = 16 5y = 16+8 5y = 24 y = 24/5 = 4.8
-8 - 5y = 12 - 9y -8 + 4y = 12 4y = 20 y = 20/4 or 5
If 5y = 4 then y = 4/5 or 0.8
If: 3y+8 = 5y-20 Then: 3y-5y = -20-8 So: -2y = -28 And: y = -28/-2 => y = 14
It's a simple linear equation in 'y'.To find the solution:7y - 8 = 2y + 37Subtract 2y from each side of the equation:5y - 8 = 37Add 8 to each side:5y = 45Divide each side by 5:y = 9