You need to be more clear about your question.
3x + 6y = 18
2x + 5y = 20
The two equations you give represent lines. I assume you're trying to find the point at which they intersect. There are various ways to work this out.
One technique is to multiply each equation by a factor that gives one of the two variables the same coefficient. For example, if we multiply the first equation by 2, and the second equation by 3, we get:
6x + 12y = 36
6x + 15y = 60
Then we can subtract one from the other, which gives us a solution for y:
[6x + 12y = 36]
- [6x + 15y = 60]
_______________
[0x - 3y = -24]
So -3y = -24, telling us that at the point of intersection, y = 8. We can then plug that back into one of the original equations and solve for x:
2x + 5y = 20
2x + 5(8) = 20
2x = 20 - 40
2x = -20
x = -10
So the lines intersect at the point (-10, 8).
Another way to work it out is to solve one of the equations for a single variable, and then plug it into the other one:
3x + 6y = 18
∴ x + 2y = 6
∴ x = 6 - 2y
2x + 5y = 20
∴ 2(6 - 2y) + 5y = 20
∴ 12 - 4y + 5y = 20
∴ y = 20 - 12
∴ y = 8
That gives us the value 8 for y, which we can once again plug in to either of the original equations to find x:
2x + 5y = 20
∴ 2x + 40 = 20
∴ 2x = -20
∴ x = -10
Once again telling us that the lines intersect at the point (-10, 8)
-3x + (-18) = 2x + 7 +18 +18 -3x = 2x +25 -2x -2x -5x = 25 ----- ----- -5 -5 x=-5 *------- equals a division line
How do you add 2x plus 3y equals 18 in 5x-y equals 11
-2x+14=20 x=-3
5x+18 = 2x+9 5x-2x = 9-18 3x = -9 x = -3 and y = 3
2 + 2x = 18 2x = 18 - 2 2x = 16 x = 8
8
2x + x + 4 +2x = x + 20 5x + 4 = x + 20 5x - x = 20 - 4 4x = 16 x = 4
2x + 10 = 182x = 8x = 4
1
2x + y = 20 y = -2x + 20 Slope = -2 m=-2
(-1, 5)
(-1, 5)