9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
48
9x2 - 12x + 4 = 0 is of the form ax2 + bx + c = 0 where the discriminant, D, can be found by D = b2 - 4ac First, you find the values of a, b and c: a = 9 b = -12 c = 4 Now you can find D: D = (-12)2 - (4)(9) = 144 - 36 = 108 D = 108
f(x) = -x3 + 9x2 - 15x - 10 => df/dx = -3x2 + 18x - 15 = -3*(x - 1)*(x - 5) df/dx = 0 => x = 1 or x = 5 So, the stationary points are x = 1 and x = 5
No.
Yes.
It is: 0
9x2 - 18x + 99(x2 - 2x + 1)==========
The discriminant is 0.
It is zero because: 182-4*9*9 = 0
No 9xx-18x+36 9(xx-2x+4) xx-2x+4 (doesn't factor evenly)
The discriminant is 0.
(-3x - 1)(3x - 7)
Factors are: 9(x - 1)(x - 1) or (3x - 3)2, so yes, it is.
TrUE
18x + 45 or 9(2x + 5) how is this answer figured?
5x2-18x+9 = (5x-3)(x-3)