x2-18x+81 = (x-9)(x-9) when factored
(x + 3)(x + 3)
(p - 9)(p - 9)
false, in order to be one 8 would have to be a square number which it is not. So the constant term in the trinomial would need to be 4, 9, 16 etc.
Yes (x+3(x+3)
4c^2-12c+9 is a trinomial because it is in the form of ax^2 + bx + c. In this case, the trinomial is a perfect square trinomial. 4c^2-12c+9 =(2c-3)(2c-3) =(2c-3)^2
Factors are: 9(x - 1)(x - 1) or (3x - 3)2, so yes, it is.
-((x + 2)(x - 9))
No, it isn't. It would be, if that "36" in the middle were "24" instead.
9x+3
factor the trinomial 16x^2+24x+9
(3X + 9) (X + 9)