Yes.
The integral of -x2 is -1/3 x3 .
(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false
-3x
8
2 2x makes no sense. If you meant the integral of 2x, it is x2 + C. If you meant the integral of 4x, it is 2x2 + C. If you meant the integral of 2x2, it is 2/3 x3 + C.
8 and 3
Factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24Factors of 24 having a difference of 5 are 3 and 8
The integral factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, and 1. Of these, 48, 24, 12, 6, and 3 are integrally divisible by 3, for a total of 5.
1, 2, 3 and 6
The paired factors of 24 are: 1 24; 2 12; 3 8; 4 6.
Write a pair of number which have a sum of 11 and a product of 24?
Factors that are multiples of 3 and factors of 24? factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. only 3, 6, 12, and 24 are multiples of 3.
Not sure what you're asking, but: The prime factorisation of 24 is: 24 = 2³ × 3 Which means its factors are: 1, 2, 3, 4, 6, 8, 12, 24 Which can be paired: 1 × 24 2 × 12 3 × 8 4 × 6 Which has the factor pair 4 × 6 which is the product of 2 composite numbers (4 = 2², 6 = 2 × 3).
The common factors of 3 and 24 are 1 and 3.
The answer is 8.
There are 12 factor pairs for 600:factor pair = 600,1factor pair = 300,2factor pair = 200,3factor pair = 150,4factor pair = 120,5factor pair = 100,6factor pair = 75,8factor pair = 60,10factor pair = 50,12factor pair = 40,15factor pair = 30,20factor pair = 25,24
1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 72, 96, 144, 288 2 and 3 are prime.