The integral of -x2 is -1/3 x3 .
(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false
-3x
8
2 2x makes no sense. If you meant the integral of 2x, it is x2 + C. If you meant the integral of 4x, it is 2x2 + C. If you meant the integral of 2x2, it is 2/3 x3 + C.
8 and 3
Factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24Factors of 24 having a difference of 5 are 3 and 8
The integral factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, and 1. Of these, 48, 24, 12, 6, and 3 are integrally divisible by 3, for a total of 5.
1, 2, 3 and 6
The paired factors of 24 are: 1 24; 2 12; 3 8; 4 6.
Factors that are multiples of 3 and factors of 24? factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. only 3, 6, 12, and 24 are multiples of 3.
The common factors of 3 and 24 are 1 and 3.
Not sure what you're asking, but: The prime factorisation of 24 is: 24 = 2³ × 3 Which means its factors are: 1, 2, 3, 4, 6, 8, 12, 24 Which can be paired: 1 × 24 2 × 12 3 × 8 4 × 6 Which has the factor pair 4 × 6 which is the product of 2 composite numbers (4 = 2², 6 = 2 × 3).
Write a pair of number which have a sum of 11 and a product of 24?
1, -1, 3, -3, 29, -29, 87, -87
1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 72, 96, 144, 288 2 and 3 are prime.
There are 12 factor pairs for 600:factor pair = 600,1factor pair = 300,2factor pair = 200,3factor pair = 150,4factor pair = 120,5factor pair = 100,6factor pair = 75,8factor pair = 60,10factor pair = 50,12factor pair = 40,15factor pair = 30,20factor pair = 25,24