2 2x makes no sense.
If you meant the integral of 2x, it is x2 + C.
If you meant the integral of 4x, it is 2x2 + C.
If you meant the integral of 2x2, it is 2/3 x3 + C.
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The integral of 2-x = 2x - (1/2)x2 + C.
Integral( sin(2x)dx) = -(cos(2x)/2) + C
I wasn't entirely sure what you meant, but if the problem was to find the integral of [sec(2x)-cos(x)+x^2]dx, then in order to get the answer you must follow a couple of steps:First you should separate the problem into three parts as you are allowed to with integration. So it becomes the integral of sec(2x) - the integral of cos(x) + the integral of x^2Then solve each part separatelyThe integral of sec(2x) is -(cos(2x)/2)The integral of cos(x) is sin(x)The integral of x^2 isLastly you must combine them together:-(cos(2x)/2) - sin(x) + (x^3)/3
First we look at the double-angle identity of cos2x. We know that: cos2x = cos^2x - sin^2x cos2x = [1-sin^2x] - sin^2x.............. (From sin^2x + cos^2x = 1, cos^2x = 1 - sin^2x) Therefore: cos2x = 1 - 2sin^2x 2sin^2x = 1 - cos2x sin^2x = 1/2(1-cos2x) sin^2x = 1/2 - cos2x/2 And intergrating, we get: x/2 - sin2x/4 + c...................(Integral of cos2x = 1/2sin2x; and c is a constant)
It seems you can't express it in terms of the standard functions used in basic calculus; the site Wolfram Alpha (input: integral sin x^2) lists the integral in terms of a so-called Fresnel function. It also lists the first terms of the infinite series.