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Can anyone explain how to solve for X in the following equation 4e raised to 3x plus 1 equals 10?
Wiki User
∙ 13y ago
Let's try natural logs.
4e^(3X+1) = 10
divide both sides by 4
e^(3X+1) = 5/2
ln[e^(3X+1)] = ln(5/2)
3X+1 lne = ln(5/2)
3X+1 = ln(5/2)/lne
( natural log of e = 1, of course )
3X + 1 = 5/2
subtract 1 from each side
3X = 3/2
divide each side by 3
X = 1/2
Wiki User
∙ 13y ago
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