2y + 2x = 20
y - 2x = 4
Add the two equations: 3y = 24 so that y = 8
Substitute this value of y in the second equation: 8 - 2x = 4
then 4 = 2x so that x = 2
Thus the ordered pair (y,x) = (8,2)
(0, 6.5) is one option.
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
There are infinitely many ordered pairs. The coordinates of each of the infinite number of points on the straight line defined by 2x + 6y = 24 (or equivalently, 3y = -x + 12) is an ordered pair that satisfies the requirements.
-x+y=12is the equation of a line and since there are infinitely many points on the line and each point is represented by an ordered pair, we have infinitely many solutions.If we take x as 0, then y must be 12so (0,12) is one ordered pair that is a solution to the equation.Zero is often a nice number to pick since it makes the calculation a bit easier.
No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.
The ordered pair is (1, 3).
(0,7)
16
(-4,3)
(-4, -6)
The ordered pair is (1, 1).
(0, 6)
(5,7)
(5,3)
No real roots.
The ordered pair is (5, 4).
The ordered pair is (-1, -2).