Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
Because you are just adding the same variable to itself, the variable does not change. in the same way that 2 + 2 is 4, 2x2 + 2x2 is 4x2.
8x2 + 15 + 26x = 8x2 + 26x + 15 = 8x2 + 20x + 6x + 15 = 4x(2x + 5) + 3(2x + 5) = (2x + 5)(4x + 3)
First, factor out the coefficient of x (in this case, 4) 4x+20----> 4(x+20/4) --> 4(x+5) then, go make yourself a sandwich.
4x(4x^2 + 3x + 1)
The answer is (2x^2+3)(4x+1)
2(x^2 + 2)(x + 3)
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No
4(x^2 + x + 3)
4(x+y)^2
5x^2(4x - 5)(5x + 11)
2x^2y^3(4x^2 - 3xy + 1)
0
-3
No solution in integers.