This is how I did it:
8x3+4x2+6x+3
[8x3+4x2]+[6x+3]
[(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:
(2x+1)(4x2+3)
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Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
Because you are just adding the same variable to itself, the variable does not change. in the same way that 2 + 2 is 4, 2x2 + 2x2 is 4x2.
8x2 + 15 + 26x = 8x2 + 26x + 15 = 8x2 + 20x + 6x + 15 = 4x(2x + 5) + 3(2x + 5) = (2x + 5)(4x + 3)
First, factor out the coefficient of x (in this case, 4) 4x+20----> 4(x+20/4) --> 4(x+5) then, go make yourself a sandwich.