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Where are the points of intersection on the x axis when y equals 8x squared -26x plus 15?
To find the points of intersection on the x-axis, set y equal to zero and solve for x. So, 8x^2 - 26x + 15 = 0. This is a quadratic equation that can be factored or solved using the quadratic formula. Once you find the values of x, those are the points of intersection on the x-axis.
How do you factor -12x2 plus 28x -15?
what is -12X squared +28X - 15? i figured it out myself. its (-6X + 5)(2X - 3).
X2 plus 15x equals -26?
x2 + 15x = -26x2 + 15x + 26 = -26 + 26x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26x = [-15 ± √(152 - 4(1)(26))]/2(1)x = (-15 ± √121)/2x = (-15 ± 11)/2x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
Factor the trinomial and enter your answer below Write each factor as a polynomial in descending order14x2 plus 29x - 15?
14x2 + 29x - 15= 14x2 + 35x - 6x - 15= 7x(2x + 5) - 3(2x + 5)= (2x + 5)(7x - 3)
8x2 - 14x - 30 by 2x - 6?
( 8x2 - 14x - 30 ) divided by ( 2x - 6 ) = 4x + 5
