Find values of x that make the tangent line to
f(x)=4x2/(x+2)
horizontal.
For a tangent line to be horizontal, its slope must be zero. The first derivative of a function will give the slope of the tangent line at any point on that function. So, by setting the first derivative of the function equal to zero and solving for x, we can find the values of x that will achieve the desired outcome.
First, to derive f(x):
Traditionally, you would use the quotient rule to derive this. If you know how to do so and prefer using the quotient rule, go ahead and do so, ignoring the next few steps. I personally don't remember the quotient rule because I always use the product rule. Essentially, I see f(x) as:
f(x)=(4x2)*(1/(x+2))
and derive it using the product rule. Doing this, I get the rough, unsimplified first derivative:
f'(x)=(4x2)*-(x+2)-2*(1)+(8x)*(x+2)-1
f'(x)=-4x2/(x+2)2+8x/(x+2)
I can add these two fractions by using a common denominator of (x+2)2:
f'(x)=-4x2/(x+2)2+(8x*(x+2))/(x+2)2
f'(x)=-4x2/(x+2)2+(8x2+16x)/(x+2)2
f'(x)=(8x2-4x2+16x)/(x+2)2
f'(x)=(4x2+16x)/(x+2)2
This final simplification is a good simplified first derivative of f(x). We must now find what x-values will cause this first derivative to equal zero. Since it is a fraction with a numerator of 4x2+16x and a denominator of (x+2)2, it will equal zero whenever the numerator is equal to zero. So, by setting just the numerator equal to zero, we get:
4x2+16x=0
Factor out as much as you can...
4x(x+4)=0
Since there are two components that are multiplied together to equal zero, setting either to zero will yield a valid solution to the above equation. So, set each equal to zero individually to get all valid values of x for your problem:
4x=0
x=0/4
x=0
and
x+4=0
x=0-4
x=-4
So, in conclusion, the two values of x that will yield horizontal tangent lines for f(x) are x=0 and x=-4 because these values will make the first derivative of f(x) equal zero.
A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
There are no exclude values of the equation, as given.
Just plug in the values for x and y. 4(-1) - 2(5) + (-1)(5) = -19
The domain of a function is the set of it's possible x values that will make the function work and output y values. In this case, it would be all the real numbers.
Domain is the number of x values that can be used and not cause an imaginary result. Range is the number of the y values that result. In f(x)=2x-5 the range is all real numbers.
mean
Speed equals distance divided by time. By rearranging that formula, we get time equals distance divided by speed.
True
Any two values which total 25
When you graph a tangent function, the asymptotes represent x values 90 and 270.
x = 90 y = 89
tangent tables are used to find values of all angles..precisely..like tan 15 degress and 25 minutes.
A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
SOHCAHTOAA way of remembering how to compute the sine, cosine, and tangent of an angle.SOH stands for Sine equals Opposite over Hypotenuse.CAH stands for Cosine equals Adjacent over Hypotenuse.TOA stands for Tangent equals Opposite over Adjacent. Example: Find the values of sin θ,cos θ, and tan θ in the right triangle 3, 4, 5. Answer:sin θ = 3/5 = 0.6cosθ = 4/5 = 0.8tanθ = 3/4 = 0.75
If: y = kx -2 and y = x^2 -8x+7 Then the values of k work out as -2 and -14 Note that the line makes contact with the curve in a positive direction or a negative direction depending on what value is used for k.
The x values are on the horizontal axis and the y values are on the vertical axis.