Since the 2 would be the x in the center coordinate (x,y) and 8 would be the y respectively they would fit into the following equation for a circle as follows: (x-h)^2 + (y-k)^2 = r^2 (x-2)^2 + (y-8)^2 = (square root of 10)^2 Remember that the 2 for the x would become negative because the equation states that the h value becomes negative....same for the y value as well. The final equation after squaring the square root of 10 would be: (x-2)^2 + (y-8)^2 = 10 This would be the final equation of the circle with center (2,8) and radius of root 10. Hope this helped! :) I'd guess that your question involves a circle centered at the cartesian coordinate (2,8): Your standard equation goes as follows: (x-2)2+(y-2)2=10 x2+y2-4x-16y+58=0 for circle with centre at(2,8) and radius the squareroot of 10. (x-2)^2 + (y-8)^2 = 10
Assuming that 1inch is your diameter, your radius is, of course, 0.5. Since the area of a circle is expressed asA=(pi)r2simply plug in the radius to this equation. You will get your area to be pi*0.25in2, which is roughly equal to 0.78539inches2.
Divide the area by pi then square root your answer which will give the radius of the circle and use 2*pi*radius to find the circumference.
The area of a circle is calculated by multiplying pi by r2. Where r = the radius of the circle. IF we use 3.1416 as our value of pi, this means that a circle with a radius of 1 inch has an area of 3.1416 square inches. Rounding this to one decimal place gives us 3.1 square inches. Other radius - area ratios are 2 .......... 12.5665 - rounded = 12.6 3 .......... 28.2744 - rounded = 28.3 4 .......... 50.2656 - rounded = 50.3 5 .......... 78.54 - - - rounded = 78.5 6 ......... 113.0976 - rounded = 113.1 7 ......... 153.9384 - rounded = 153.9 8 ......... 201.0624 - rounded = 201.1 9 ......... 254.4696 - rounded = 254.5 10 ....... 314.16 - - - rounded = 314.2
x2 + y2 - 10x + 4y - 52 = 0 x2 - 10x + y2 + 4y = 52 Complete the square (x2 - 10x + 25) + (y2 + 4y + 4) = 52 + 25 + 4 (x - 5)2 + (y + 2)2 = 81 (x - 5)2 + (y - -2)2 = 92 This is the equation of a circle with center (5, -2), and radius 9.
not cool
It is the equation of a circle with radius of 6 and its center at the origin.
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
A circle has a radius because each radius is the same. A square does not because if it did, not every radius would be the same. Since a square is a regular polygon, it has an apothem, which goes from the center to the middle of a side, so it doesn't need a radius.
The area of a circle is given by: pi multiplied by the square of the radius. So if the radius is 15, the area is 225pi (225 is 15 squared)
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
A square does not have a radius, as a radius is a line segment that connects the center of a circle to any point on its circumference. In a square, the equivalent of a radius would be the distance from the center to a vertex, which is half the length of a diagonal. To find this distance, you can use the Pythagorean theorem by dividing the length of one side by the square root of 2.
A circle with radius 15mm will fit in a 30mm square. Find the intersection of the square's diagonals, that is the center of the circle.
Area of the circle in square inches = pi*82
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Equation for the area circle = pi x radius squared If the area is 144pi, then you need to find the square root of 144, which is 12. Therefore, radius = 12
If x^2 plus y^2 = 169 then the center of the circle is at (0, 0) and its radius is the square root of 169 which is 13
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.