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Give the equation for a circle center at 2 and center 8 and radius the square the root of 10?
Wiki User
∙ 15y ago
Since the 2 would be the x in the center coordinate (x,y) and 8 would be the y respectively they would fit into the following equation for a circle as follows: (x-h)^2 + (y-k)^2 = r^2 (x-2)^2 + (y-8)^2 = (square root of 10)^2 Remember that the 2 for the x would become negative because the equation states that the h value becomes negative....same for the y value as well. The final equation after squaring the square root of 10 would be: (x-2)^2 + (y-8)^2 = 10 This would be the final equation of the circle with center (2,8) and radius of root 10. Hope this helped! :) I'd guess that your question involves a circle centered at the cartesian coordinate (2,8): Your standard equation goes as follows: (x-2)2+(y-2)2=10 x2+y2-4x-16y+58=0 for circle with centre at(2,8) and radius the squareroot of 10. (x-2)^2 + (y-8)^2 = 10
Wiki User
∙ 15y ago
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