That is, 0 <= x < oo, where oo is the closest analog to the "infinity" symbol in this typeface, and <= means less than or equal to. Thus, x is a member of the set [0, oo).
I think you mean zero to negative infinity is {x: x< or equal to 0}
This is too simple to be in Calculus. The answer is 1
It is indeterminate. There are many other inderterminate forms. It is not at all the same as 3/3 for example. You can see this with limits and some calculus rules. You must apply the L'Hospital theorem by deriving the numerator and the denominator of the equation that gave you infinity over infinity.-----------------Why ∞/∞ is not 1One could think that ∞/∞ = 1, but this is wrong.The answer depends on the kind of infinity: in fact, there are different kinds of infinity.For example, consider f(x) = x2 and g(x) = x. In the limit x→∞ of the function f(x)/g(x), we havelimx→∞ f(x)/g(x) = limx→∞ x2/x = limx→∞ x = ∞;so, both f(x) and g(x), in that limit, equal infinity, but f(x)/g(x) ≠ 1. If we have f(x) = 2x and g(x) = x, both f(x) and g(x) equal infinity (for x→∞), butlimx→∞ f(x)/g(x) = limx→∞ 2x/x = limx→∞ 2 = 2 ≠ 1.So you see that infinity is something to check everytime!--------------Addition: Since infinity is not a set number, you cannot assume that infinity divided by infinity would equal one. Infinity is an indeterminate number.1To touch on this whatever you take and divide by the same number will always give you one.2Infinity divided by infinity is not equal to 1, But it is undefined, not another infinity. This would help you:First, I am going to define this axiom (assumption) that infinity divided by infinity is equal to one:∞-∞= 1Since ∞ = ∞ + ∞, then we are going to substitute the first infinity in our axiom:∞ + ∞---∞= 1The next step is to split this fraction into two fractions:∞-∞+ ∞-∞= 1Next, substitute the axiom twice into the equation, we get:1 + 1 = 1Finally, this can be rewritten as:2 = 1Therefore, infinity divided by infinity is NOT equal to one. Instead we can get any real number to equal to one when we assume infinity divided by infinity is equal to one, so infinity divided by infinity is undefined.
When we divide 1 by infinity, we are essentially taking the limit of 1 as the denominator approaches infinity. In mathematics, this limit is equal to zero. This is because as the denominator becomes infinitely large, the value of the fraction approaches zero. Therefore, 1 divided by infinity equals 0.
When the first derivative of the function is equal to zero and the second derivative is positive.
X = (-infinity, 0) U (0, infinity) The above is read as X equals negative infinity, comma zero, union, zero, comma infinity on an open interval (By the way, this interval is made up of two intervals). A parenthesis by a value indicates it is not included. This means X could equal anything between -infinity and 0 and X can equal anything between 0 and infinity. X can not equal -infinity. X can not equal 0. X can not equal infinity. The interval is open because none of the starting or ending values can be a value of X (It's a parenthesis by all the starting and ending values). There is a parenthesis by 0 because 0 is not a possible value of X (the question says so). There is a parenthesis by -infinity and infinity because they are not real numbers. So whether either of them is included in the answer, they always have a parenthesis by them. If a number was included in an interval, there would be a square bracket by it, like this: [ or ]. If the starting number and the ending number on the interval is included then the interval is closed.
Yes. Multiplying a negative number by a very large positive number will equal a large negative number. If you have the function y = -x, then as x approaches infinity, y will approach negative infinity at the same rate.
I think you mean zero to negative infinity is {x: x< or equal to 0}
x is equal to or less than -3 means that x is every number from -3 onwards all the way to negative infinity. For example, -4 would be less than -3, -5 would be less than -4 which is less than -3 and so forth. So for the final answer, the interval of x that is equal to or less than -3 would be written like this: (-inf,-3] There is a parenthesis on negative infinity because it is impossible to reach infinity and since x is equal to -3, we put the brackets to indicate that the -3 is included in the interval.
X doesn't have to equal to 4, it can be equal to any real number really (as in, not i), the really important part is that Y is equal to both Positive and Negative Infinity, just like in a horizontal line Y can be equal to any real number, but, in this case, X has to be equal to both Positive and Negative Infinity.
The answer to this is 2, and 0.
If the exponent is not negative, then a number written in scientific notation is greater than or equal to 1.
The set of all real numbers less than or equal to -6 can be represented as (-∞, -6]. This notation indicates that the set includes all real numbers from negative infinity up to and including -6. In interval notation, the square bracket [ denotes that -6 is included in the set, while the parentheses ( indicate that negative infinity is not a specific value in the set.
It is still infinity.
An interval separates the distance between two numbers into equal parts. For example, the number 4 is an interval for the number 3 and the number 5.
both are equal... infinity is the representation of undefined.
it just equal infinity