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What is Infinity divided by Infinity?
It is indeterminate. There are many other inderterminate forms. It is not at all the same as 3/3 for example. You can see this with limits and some calculus rules. You must apply the L'Hospital theorem by deriving the numerator and the denominator of the equation that gave you infinity over infinity.-----------------Why ∞/∞ is not 1One could think that ∞/∞ = 1, but this is wrong.The answer depends on the kind of infinity: in fact, there are different kinds of infinity.For example, consider f(x) = x2 and g(x) = x. In the limit x→∞ of the function f(x)/g(x), we havelimx→∞ f(x)/g(x) = limx→∞ x2/x = limx→∞ x = ∞;so, both f(x) and g(x), in that limit, equal infinity, but f(x)/g(x) ≠ 1. If we have f(x) = 2x and g(x) = x, both f(x) and g(x) equal infinity (for x→∞), butlimx→∞ f(x)/g(x) = limx→∞ 2x/x = limx→∞ 2 = 2 ≠ 1.So you see that infinity is something to check everytime!--------------Addition: Since infinity is not a set number, you cannot assume that infinity divided by infinity would equal one. Infinity is an indeterminate number.1To touch on this whatever you take and divide by the same number will always give you one.2Infinity divided by infinity is not equal to 1, But it is undefined, not another infinity. This would help you:First, I am going to define this axiom (assumption) that infinity divided by infinity is equal to one:∞-∞= 1Since ∞ = ∞ + ∞, then we are going to substitute the first infinity in our axiom:∞ + ∞---∞= 1The next step is to split this fraction into two fractions:∞-∞+ ∞-∞= 1Next, substitute the axiom twice into the equation, we get:1 + 1 = 1Finally, this can be rewritten as:2 = 1Therefore, infinity divided by infinity is NOT equal to one. Instead we can get any real number to equal to one when we assume infinity divided by infinity is equal to one, so infinity divided by infinity is undefined.
What is 1 divided by infinity?
When we divide 1 by infinity, we are essentially taking the limit of 1 as the denominator approaches infinity. In mathematics, this limit is equal to zero. This is because as the denominator becomes infinitely large, the value of the fraction approaches zero. Therefore, 1 divided by infinity equals 0.
What is the set-builder notation of the problem the set of negative infinity and 0?
I think you mean zero to negative infinity is {x: x< or equal to 0}
Domain of t squared plus 1?
If t is real then [1 to infinity) ie all real numbers from 1 to infinity, including 1 but not infinity. If t is in the complex plane then the domain of t^2+1 is also the complex plane.
How do write in interval notation 0 is less than or equal to x while x is less than positive infinity?
That is, 0
