x^(3) + 125 =>
x^(3) + 5^(3)
This factors to
(x + 5)(x^(2) - 5x + 5^(2) ) or (x + 5)(x^(2) - 5x + 25)
NB The clue is to spot that the constant (125) is a cubic numbers ( 5^(3)).
Similarly with other 'cubic factorings'.
It is: 1/1251/125 (1 over 125)
11.180339....11.18 rounds to 11.2.The square root of 125 is about 11.18
Y^2 = 125 Y = +/- sqrt(125) Y = +/- 5sqrt(5)
168.19 CAD
Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100
125
13
w3+125
It equals 125 5x5x5=125
1/125
125
125
5 to the third power equals 125
To find the number whose third power equals 125, we need to determine the cube root of 125. The cube root of 125 is 5, since (5^3 = 5 \times 5 \times 5 = 125). Thus, the number that, when raised to the third power, equals 125 is 5.
125!! i think:P:P
5^3 is equal to 125.
It is 125/27.