x^(3) + 125 =>
x^(3) + 5^(3)
This factors to
(x + 5)(x^(2) - 5x + 5^(2) ) or (x + 5)(x^(2) - 5x + 25)
NB The clue is to spot that the constant (125) is a cubic numbers ( 5^(3)).
Similarly with other 'cubic factorings'.
Chat with our AI personalities
x^(3) + 125
= (x^3) + (5^3)
This factors into
(x + 5){x^(2) - 5x + 5^(2) }
= (x + 5)(x^(2) - 5x + 25)
The clue is to recognize that the constant (125) is a cubic number (5^3).
It is: 1/1251/125 (1 over 125)
11.180339....11.18 rounds to 11.2.The square root of 125 is about 11.18
Y^2 = 125 Y = +/- sqrt(125) Y = +/- 5sqrt(5)
168.19 CAD
Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100