∣∣2−1 . -6 + 15 = 9 To calculate the area between the curves y = 2 x2 + 1 and y = 2 x + 5, we must evaluate the integral ∫ab(2x+5)−(2x2+1)dx . To determine which values to use for a and b as the limits of the integral, we calculate the x values where the two curves intersect. Solve 2 x2 + 1 = 2 x + 5 by factoring to get x = 2 and x = -1. Set a = -1, b = 2. The enclosed area, A , is therefore given by the equation A=∫2−1(2x+5)−(2x2+1)dx=∫2−1−2x2+2x+2x+4 dx=[−2x33+x2+4x]
You draw the line X - Y = 0 or, equivalently, X = Y. Since points on the line are included in the desired region, the line should be solid. Then the required region is the area of the line and all points above it.
A line. The derivative of a function is its slope. If the slope is a constant then the graph is a line.
Take a blank graph with 'x' and 'y' axes on it. Draw a 45-degree line on the graph. The line goes through the origin, and from the origin, it goes down-left and up-right. The slope of the line is 1, and its equation is y=x. The region "y is greater than or equal to x" is every point on that line, plus every point on the side above it (to the left of it).
The steepness of a line graph is called the "gradient" ------------------------------- or slope.
Draw a graph of a given curve in the xoy plane. Now draw a vertical line so that it cuts the graph. If the vertical line cuts the graph in more than one ordinate then given graph is not a function. If it cuts the graph at a single ordinate such a graph is a function.(is called vertical line test)
In the subject art an area enclosed by a line is a shape.
The boundary line is solid. If not it will be a dashed line.
The graph of an inequality is a region, not a line.
An area graph. It fills the area between a line and the line below or the x-axis.
First draw a dashed line for y = 2x and then highlight the are above the line. You can highlight the area by shading it and state that the shaded area is the region of interest, or (my preference) shading the area below the line and state that the unshaded area is the region of interest. The advantages of the second option become clearer when you have several inequalities defining a region.
You draw the line X - Y = 0 or, equivalently, X = Y. Since points on the line are included in the desired region, the line should be solid. Then the required region is the area of the line and all points above it.
line graph!
The graph of y > - x is an area, firstly draw the line y = -x which is a line sloping diagonally upwards to the left at 45o and the area where y > -x is the area above the line
A polygon.
It can represent the graph of a strict inequality where the inequality is satisfied by the area on one side of the dashed line and not on the other. Points on the line do not satisfy the inequality.
line graph x line graph = divided line graph
plane