The circle is 100% or 100/100.
You want 1/8 of 100. that's (1/8)*100=100/8=12,5%
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The Unit Circle is a circle that has a radius of 1 and a center at the origin. If you look at the unit circle 90 degrees is at the point (0,1). Cosine is equal to the x value of a point on the Unit Circle. The line created to the point (0,1) on the unit circle when the degree is 90 is completely vertical, which in turn makes the x value 0 and thus, cosine of 90 = 0. Read more >> Options >> http://www.answers.com?initiator=FFANS
Assuming that 1inch is your diameter, your radius is, of course, 0.5. Since the area of a circle is expressed asA=(pi)r2simply plug in the radius to this equation. You will get your area to be pi*0.25in2, which is roughly equal to 0.78539inches2.
On the unit circle sin(90) degrees is at Y = 1 and as that is on the Y axis X will equal = 0. Ask yourself. Where would 90 degrees be on a 360 degree circle? Straight up.
This is a fairly straightforward trigonometry problem. I'll assume you were give tan(θ)=(-1) for 0o < θ < 360o in this situation. I strongly suggest you familiarize yourself with the unit circle. In this case, we are looking for a point on the circle where the slope between (0,0) and the point at θ is (-1). This occurs at 135o and 315o. Short Answer: θ = {135o, 315o}
Given: f(x)=3x^2+6x-2 To find x: x= -b/2a x= -6/2(3) x= -1 to find y, replace x with -1: f(-1)=3(-1)^2+6(-1)-2 y=3(1)-6-2 y= -5