This is a fairly straightforward trigonometry problem.
I'll assume you were give tan(θ)=(-1) for 0o < θ < 360o in this situation.
I strongly suggest you familiarize yourself with the unit circle. In this case, we are looking for a point on the circle where the slope between (0,0) and the point at θ is (-1). This occurs at 135o and 315o.
Short Answer: θ = {135o, 315o}
Sin (theta + 180) is equal to -sin (theta) because the sin function is symmetrically opposite every 180 degrees. Proof: Draw a unit circle, radius 1, centered at the origin (x=0, y=0). Pick any point on that circle, and draw a line from that point through the origin and to the opposite edge of the circle. The angle between that line and the x-axis going to the right is theta. It ranges from 0 degrees at (x=1, y=0) to 360 degrees coming back to (x=1, y=0) rotating counter-clockwise. (The angle is called theta to avoid confusion with the question's original use of x.) The x and y coordinates of the first point are symmetrically opposite the x and y coordinates of the second point. (If X1 were 0.35, for instance, then X2 would be -0.35.) The same goes for Y. (There are two right triangles, with the hypotenuses equal and two angles equal; therefore the two triangles are the same, just flipped over.) Sin (theta) in a unit circle is defined in trigonometry as y, so sin (theta + 180) is equal to -y, which is the same as -sin (theta). Sin (theta) is actually y divided by hypotenuse or "opposite over hypotenuse" but, since the hypotenuse is 1, that can be ignored - it does not change the answer.
360 - 301 = 59
Essentially, none. Every negative angle can be made positive by adding 2*pi radians (or 360 degrees, or a multiple).
Because it is an quadrilaterial with four equal sides that sum up to 360
0 ================================== Another contributor says: Yes, x=0 is a solution, but there are a lot more. sin(2x) = sin(x) whenever x = (N pi) radians or x = (2N-1) pi / 3 radians. 1 radian = 57.3 degrees (rounded) Make ' N ' any whole number you want. The first cycle of angles are: X = pi/3, pi, 5 pi/3, 2 pi radians or 60, 180, 300, 360 degrees.
108.435 degrees 288.435 degrees (decimal is rounded)
The answer is 60 and 240 degrees. Add radical 3 and inverse tan to get answer add 180 for other answer less than 360.
4Sin(theta) = 2 Sin(Theta) = 2/4 = 1/2 - 0.5 Theta = Sin^(-1) [0.5] Theta = 30 degrees.
Cos(360 - X) = Trig. Identity Cos(360)Cos(x) + Sin(360)Sin(x) => 1CosX + 0Sinx => CosX + o => CosX
-0.5736
They are 35.1 and 324.9 degrees.
2 sin (Θ) + 1 = 0sin (Θ) = -1/2Θ = 210°Θ = 330°
No, not necessarily. Cosine theta is equal to 1 only when theta is equal to zero and multiples of 2 pi radians or multiples of 360 degrees. This is because cosine theta is hypotenuse over adjacent, and the ratio 1 only occurs at 0, 360, 720, etc. or 0, 2 pi, 4 pi, etc.
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
The work done by a force can be calculated using the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Assuming the force is in the direction of motion (theta = 0), the work done would be 360 Joules (60 N * 6 m).
The empirical formula for the number of images formed by two inclined mirrors is [ n = \frac{360}{|180-\theta|} ], where (\theta) is the angle between the mirrors. This formula is derived from the concept that each additional image is created when the extended reflected light rays meet at intervals of (\frac{360}{|180-\theta|}) degrees.
Given that theta is the angle with respect to the positive X axis of a line of length 1, then sin(theta) = Y and cos(theta) is X, with (X,Y) being the point at the end of the line. As theta sweeps from 0 to 360 degrees, or 0 to 2 pi radians, that point draws a circle of radius 1, with center at (0,0).Since X, Y, and 1 form the sides of a right triangle, where 1 is the hypotenuse, then the pythagorean theorem states that X2 + Y2 = 12. This means that sin2(theta) + cos2(theta) = 1.Tan(theta) is defined as sin(theta) divided by cos(theta), or Y / X. Since division by zero is a limiting invalidity, then tan(theta) is asymptotic to Y=0, having value of +infinity at theta = 90 or pi / 4, and -infinity at 270 or 3 pi / 4.